How do I remove NaN values from a matrix and retain matrix shape?

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Manny Kins
Manny Kins 2019 年 4 月 3 日
コメント済み: Les Beckham 2023 年 6 月 8 日
Say for example I have the following array
X = [1 3 4; 5 6 8; NaN NaN NaN]
X =
1 3 4
5 6 8
NaN NaN NaN
I want to get rid of all the NaN values so I use
X(~isnan(X))
ans =
1
5
3
6
4
8
Now the array has changed from a 3x3 to a 1x6. I want to be able to retain the matrix layout and only remove the NaN values giving a 2x3
X =
1 3 4
5 6 8
Thanks

採用された回答

madhan ravi
madhan ravi 2019 年 4 月 3 日
X(all(isnan(X),2),:)=[]
  1 件のコメント
Manny Kins
Manny Kins 2019 年 4 月 3 日
Thank you for your quick response! This is a very elegant solution that can be applied to much larger matrices!

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その他の回答 (1 件)

Monik gupta
Monik gupta 2023 年 6 月 8 日
Is there any way to remove NaN values without changing shape of the matrix? in case matrix is like following:
X = [1 3 4; 5 NaN 8; 3 4 NaN];
Thanks in Advance.
  1 件のコメント
Les Beckham
Les Beckham 2023 年 6 月 8 日
You really shouldn't ask questions using an answer to someone else's question.
Nevertheless...
You can't remove them, but you can replace them with something other than NaN. Only you can decide what value to use for the replacement in your particular application.
For example, this will replace them with zero:
X = [1 3 4; 5 NaN 8; 3 4 NaN]
X = 3×3
1 3 4 5 NaN 8 3 4 NaN
X(isnan(X)) = 0
X = 3×3
1 3 4 5 0 8 3 4 0

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