Error finding matrix indices where elements obey a condition

Hi,
I have a (30,1) matrix A filled with both positive and negative double values with high precisions.
I do the B= A>0 expecting a resulting matrix filled with 0s and 1s based on the value of original matrix such as
[0,
0,
1,
1,
0,
....]
However, when I display I get a matrix like below
0.0 < -60.80089912054130723383673691361028456512560544254638307756720395046146077078219605027697980403900146484375
0.0 < -40.47441497086561319883182687840919573785507473004455923328153712191512791918057700968347489833831787109375
0.0 < 11.9150901590727927897158716535914255438713276913571208738565018227240077663964257226325571537017822265625
0.0 < 50.24337655630030618369864852262179095255359883940103235308691394245261818696235422976315021514892578125
0.0 < -12.788094842081277874683606597932106962408104528383932295293478643982698628178695798851549625396728515625
0.0 < -19.7994345791724984686511623375698392780606832842132285447736268595153585891921466100029647350311279296875
0.0 < 44.20960440529531749044620672799080999950637846265719961065220598196712220584458918892778456211090087890625
0.0 < -38.4752715808701180299125340913012275096601820744906678455217984013980725421788520179688930511474609375
0.0 < -57.1261686699021779161260124218737353314343618323505877827184033790341999292650143615901470184326171875
0.0 < -15.50675798085333259859508957067109961395543474125240585269404109021451620975540208746679127216339111328125 0
Later when use matrix B in a matrix multiplication I get a lot of NaN values. Where am I doing wrong? I will be very appreciated if I can find a solution dfor this . Cause I am struggling due to this issue for a few days..
Best Regards,
Ferda

7 件のコメント

madhan ravi
madhan ravi 2019 年 3 月 22 日
please attach your 30 by 1 matrix as a .mat file
ferda sonmez
ferda sonmez 2019 年 3 月 22 日
I attached. However, when I look mat file I saw a content like
1x1 sym
1x1 sym
1x1 sym
....
I don't know what this points out.. Thank you for your interest.
Luna
Luna 2019 年 3 月 22 日
Ferda, what is the source of your saved .mat file? Did you saved it yourself from your workspace?
ferda sonmez
ferda sonmez 2019 年 3 月 22 日
yes I saved it usign the below code
save("Matrix_Saved.mat", 'input_of_hidden_layer2');
Luna
Luna 2019 年 3 月 22 日
As far as I understand your data already symbolic in your workspace. You should convert it into double array see my answer below.
You can also convert it before saving, when you load you will get the double array instead of symbolic array.
A = double(input_of_hidden_layer2)
save('SavedMatrix1.mat','A')
load('SavedMatrix1.mat') % you will see A 30x1 double in your workspace.
madhan ravi
madhan ravi 2019 年 3 月 22 日
When you use vpa() or vpasolve() the class of the variable becomes symbolic.
Luna
Luna 2019 年 3 月 25 日
Ah now I understand, thx :)

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 採用された回答

Luna
Luna 2019 年 3 月 22 日

0 投票

Hi Ferda,
Please see my comments below:
% first convert it to double array:
A = double(input_of_hidden_layer2);
% indexing your conditions:
B = A > 0;
% get the values which are greater than zero from that index:
A(B)

2 件のコメント

ferda sonmez
ferda sonmez 2019 年 3 月 27 日
Thank you for your answer :)
Luna
Luna 2019 年 3 月 28 日
Your welcome :)

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その他の回答 (1 件)

Walter Roberson
Walter Roberson 2019 年 3 月 23 日

1 投票

B = isAlways(A>0);
will give you a logical result. Or you could
B = logical(A>0);

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2019 年 3 月 22 日

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2019 年 3 月 28 日

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