Creating a line with different steps
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The idea is to plot some kind of staircase with sloped steps. I made this code, it runs but it doesn't plot a graph, any ideas what went wrong?
h=5
for x = [0.2:0.2:100]
if x == [0.2:1:100]
y = h*x
elseif x == [0.4:1:100]
y= h*x
elseif x == [0.6:1:100]
y = h*x
elseif x == [0.8:1:100]
y= h*x - 0.2*h
else x == [1:1:100]
y= h*x-0.4*h
end
end
plot(x,y)
1 件のコメント
madhan ravi
2019 年 3 月 13 日
編集済み: madhan ravi
2019 年 3 月 13 日
expected graph picture ?, you seem to be plotting a point, are you aware of stairs() ?
回答 (1 件)
KALYAN ACHARJYA
2019 年 3 月 13 日
編集済み: KALYAN ACHARJYA
2019 年 3 月 13 日
it runs but it doesn't plot a graph, any ideas what went wrong?
You can check the x and y value-
x =
100.000000000000e+000
>> y
y =
498.000000000000e+000
It's having single point, it just plot one point, that why not visible as line or graph.
From the statement
for x =[0.2:0.2:100] get last iteration value x=100 and from any one if else statement single y valie is assigned.
See the point
plot(x,y,'*','linewidth',30);

Hope your doubt is cleared.
2 件のコメント
KALYAN ACHARJYA
2019 年 3 月 13 日
編集済み: madhan ravi
2019 年 3 月 13 日
@Joyce You can do that in multiple ways, I have tried the way what you have tried so far. Please do the needful change as your required output.
x=[0:0.1:10];
h=2;
for i=1:length(x);
if x(i)<1
y(i)=h*x(i);
elseif x(i)>=1 & x(i)<2
y(i)=h*x(i)+3*h;
elseif x(i)>=2 & x(i)<3
y(i)=h*x(i)+4*h;
elseif x(i)>=3 & x(i)<4
y(i)=h*x(i)+5*h;
else
y(i)=h*x(i)+6*h;
end
end
plot(x,y)

You can change the shape of the curve (whether staircase or ramp) by changing the step and multiplication factor in 2nd part of expression 3*h. You can take the h as common and add constant value with x(i).. same thing.
Hope you get the idea and expecting it helps to way out from the issue.
Thanks and regards
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