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How can i generalize what is inside the ndgrid function?

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metehan akinci
metehan akinci 2019 年 3 月 10 日
コメント済み: metehan akinci 2019 年 3 月 13 日
I have a Values Matrix
Values={[3 4],[2],[3 4 5]} %% which is randomly created.
[Numbers{1:length(Values)}]=ndgrid(Values{1},Values{2},Values{3}); which i want to find.
The problem is that i want to generalize the right sidet so that if Values changes i dont want to re-write my code again.
This is what i tried but couldnt worked it out
for i=1:length(Values)
c(i)={'Values'};
end
Pattern=strjoin(strcat(c,'{%d}'),',');
for a=1:length(Values)
b(a)=a;
end
a=sprintf(Pattern,b) %%%%% which gives me Values{1},Values{2},Values{3}
when i put it in a ndgrid function it doesnt give me the correct answer.
ndgrid(a)
How can i solve this problem? Thanks!
  2 件のコメント
Stephen23
Stephen23 2019 年 3 月 11 日
編集済み: Stephen23 2019 年 3 月 11 日
You are already using a comma-separated list on the LHS, just use one on the RHS as well, as Walter Roberson showed:
Numbers = cell(1,numel(Values));
[Numbers{:}] = ndgrid(Values{:})
For more information on comma-separated lists see:
metehan akinci
metehan akinci 2019 年 3 月 13 日
Thanks sir

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採用された回答

Walter Roberson
Walter Roberson 2019 年 3 月 10 日
編集済み: Walter Roberson 2019 年 3 月 10 日
nv = length(Values);
Numbers = cell(nv, 1);
[Numbers{:}] = ndgrid(Values{:});

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