How to count the number of nonzero numbers in a row.

I having a matrix A=[ 0 0 0 0 0.4 0 0 0.3;

0.1 0 0 0.7 0 0.2 0 0 0;

0 0 0.6 0 0 0 0 0.9]

I want to count the number of elements which is not equal to zero present in each row

the answer will be A=[2;

3;

2]

I tried with the command

D=(numel(A~=0),1)

But unable to get the result.Could anyone please help me on this.

Answer 1

[KSSV]

Read about nnz

A=[ 0  0  0  0  0.4  0  0  0.3;
   0.1  0  0  0.7  0  0.2  0  0  ;
   0  0  0.6  0  0  0  0  0.9] ;

[m,n] = size(A) ;
iwant = zeros(m,1) ; 
for i = 1:m
    iwant(i) = nnz(A(i,:)) ;
end
iwant

Answer 2

[madhan ravi]

No loops needed:

sum(A~=0,2)

[Jan]

+1. Most efficient solution.

[madhan ravi]

@Jan: Thank you!