hypothetical matlab's limit
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Hi everyone. I have to calculate a sumof a vector of doubles of 1x4884 components. When I use this function i get as ans=nan. I there a limit to the maximum number that matlab is able to calculate? If yes how can i change this cobstraint?
Thank you in advance
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Adam Danz
2019 年 2 月 9 日
編集済み: Adam Danz
2019 年 2 月 9 日
I'm sure there is such a limit in Matlab but it's nowhere near a vector length of 4884.
The problem is that you have at least 1 NaN value in your data.
sum([1, NaN])
ans =
NaN
Use the 'omitnan' flag to ignore NaN values.
sum([1,NaN], 'omitnan')
ans =
1
To confirm that you have at least one NaN value in your data, if this next line returns True (1), you have NaN value(s).
any(isnan(yourData)) % to find where the NaNs are: find(isnan(yourData))
And here's a test to confirm that Matlab can handle vector lengths of 4884 (or even 4884000 for that matter).
sum(rand(1, 4884))
7 件のコメント
Adam Danz
2019 年 2 月 9 日
This Matlab summary covers most of your examples and also mentions rem(x,y) when x is inf or y is 0.
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