How can I put these subplots into a for loop?

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Maria Y
Maria Y 2019 年 2 月 8 日
コメント済み: Adam Danz 2019 年 2 月 8 日
Hello,
I've created these subplots which takes 300 seconds of data and chops it into 10 separate subplots of 30 second portions. I clearly did it manually here and I know there is a way to make it more efficient with a for loop, but i'm getting a bit confused on which values to choose to replace.
Thanks in advance for any and all help!
%% Load data
BR_file=dir('BRRAW*.mat');
load(BR_file.name);
%% Initialize
signal=[brraw.ecog, brraw.lfp]';
a=length(signal);
timex=[0:1/794:a/794];
timex(a+1)=[];
%% Subplots of 300 seconds of data chopped into 30 second portions
subplot(5,2,1)
time30=find(timex==30);
x=linspace(1,30);
hold on
plot(timex(1:time30),signal(1:time30));
subplot(5,2,2)
time60=find(timex==60);
x=linspace(30,60);
hold on
plot(timex(time30:time60),signal(time30:time60));
subplot(5,2,3)
time90=find(timex==90);
x=linspace(60,90);
hold on
plot(timex(time60:time90),signal(time60:time90));
subplot(5,2,4)
time120=find(timex==120);
x=linspace(90,120);
hold on
plot(timex(time90:time120),signal(time90:time120));
subplot(5,2,5)
time150=find(timex==150);
x=linspace(120,150);
hold on
plot(timex(time120:time150),signal(time120:time150));
subplot(5,2,6)
time180=find(timex==180);
x=linspace(150,180);
hold on
plot(timex(time150:time180),signal(time150:time180));
subplot(5,2,7)
time210=find(timex==210);
x=linspace(180,210);
hold on
plot(timex(time180:time210),signal(time180:time210));
subplot(5,2,8)
time240=find(timex==240);
x=linspace(210,240);
hold on
plot(timex(time210:time240),signal(time210:time240));
subplot(5,2,9)
time270=214381;
x=linspace(240,270);
hold on
plot(timex(time240:time270),signal(time240:time270));
set(gca,'Xlim',[240 270]);
subplot(5,2,10)
time300=find(timex==300);
x=linspace(270,300);
hold on
plot(timex(time270:time300),signal(time270:time300));

採用された回答

Adam Danz
Adam Danz 2019 年 2 月 8 日
編集済み: Adam Danz 2019 年 2 月 8 日
Since we don't have access to your data, I've made some assumptions. Most importantly, I'm assuming 'timex' is monotonically increasing. If that's not correct, my solution won't work. Also, I did not include the x=linspace() line since you don't seem to be using that.
% define subplot layout
nrow = 5;
ncol = 2;
keyTimes = [0:30:300]; %you can probably come up with a better name for this variable
% Loop through each subplot
for i = 1: length(keyTimes)-1
subplot(nrow, ncol, i)
hold on %if needed
idx = timex >= keyTimes(i) & timex <=keyTimes(i+1);
plot(timex(idx), signal(idx))
end
  5 件のコメント
Maria Y
Maria Y 2019 年 2 月 8 日
Sorry, had your corrected version open in a different tab. Looks perfect, thanks so much for your help!
Adam Danz
Adam Danz 2019 年 2 月 8 日
Nice! Glad I could help.

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