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Can I Split the char with out deliminater ? (Please have a look at example)

Rakesh Yadav Kodari さんによって質問されました 2019 年 2 月 5 日
最新アクティビティ Rakesh Yadav Kodari さんによって コメントされました 2019 年 2 月 5 日
For example if I have char Data = FD86FA78F79B0425FAEE0866031E02F60742F9840240F6C0F999FE4BF6F407FDFE2208330680FEB20680F6;
and i have no deliminater to split it, but ineed to split it in to 4 chars each
Expected ans = FD86
FA78
F79B
0425 and so on till end
and convert them in to Decimal(they are in Hex form)

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2 件の回答

回答者: Stephen Cobeldick
2019 年 2 月 5 日
編集済み: Stephen Cobeldick
2019 年 2 月 5 日
 採用された回答

>> str = 'FD86FA78F79B0425FAEE0866031E02F60742F9840240F6C0F999FE4BF6F407FDFE2208330680FEB20680F6';
>> sscanf(str,'%4x')
ans =
64902
64120
63387
1061
64238
2150
798
758
1858
63876
576
63168
63897
65099
63220
2045
65058
2099
1664
65202
1664
246
Note that your example character vector's length is not a multiple of four: you should check this before converting, otherwise you might get unexpected values. You need to decide if non-multiple-of-four lengths require special handling.

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YT
Answer by YT
on 5 Feb 2019

I don't want to critize too much, but it just seems you're asking so many question on the same dataset that its almost like the volunteers on this forum are doing all your work for you. Therefore I wont give you the code, but here's a question which is similar when it comes to splitting strings. And I suggest you look in the documentation for converting decimal to hexadecimal.

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