explain computation of P2(1:L/2+1)
    10 ビュー (過去 30 日間)
  
       古いコメントを表示
    
What exacly does P2(1:L/2+1) this 
where L is length of signal and P2 is two sided spectrum
P1 =  P2(1:L/2+1)
0 件のコメント
回答 (1 件)
  Omer Yasin Birey
      
 2019 年 2 月 5 日
        
      編集済み: Omer Yasin Birey
      
 2019 年 2 月 5 日
  
      It takes one more element than half of it. Let's say your array is 
P2 = [1 2 5 6 7 8 9];
L = length(P2);
P2(1:L/2+1)
the output of this will be
[1 2 5 6]
Because the length is 7 and (7/2+1) will be 4 (it is 4 because for odd numbers it will round down the result of dividing operation). And it will take until 4th element. 
3 件のコメント
  Omer Yasin Birey
      
 2019 年 2 月 5 日
				Hard to tell with a single line code. Also after his edit it still seems like he wants to know what syntax does
  P Sun
 2021 年 6 月 10 日
				Well, I know neither and it is great to know the syntax part. 
This line from intro of fft https://uk.mathworks.com/help/matlab/ref/fft.html
参考
カテゴリ
				Help Center および File Exchange で Spectral Measurements についてさらに検索
			
	Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!



