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How to store all the datas of a txt file in some given bits?

Jiajie Zhang さんによって質問されました 2019 年 1 月 20 日
最新アクティビティ Walter Roberson
さんによって 回答されました 2019 年 1 月 21 日
I have a txt like this:
9,15,5,10,14,5,11,15,5,7,19,0,4,22,0
7,8,7,10,8,4,11,7,0,9,12,7,11,11,0
each row has 15 data values; actually it's a set of 5 points with three atrributions.
such as, the first point is (9,15,5),9 and 15 are x and y direction of a point, 5 is the orientation,
I want to use 4 bits to store x and y, 3 bits to store orientation.
and then store all the data after transformation in a new txt file.
The sample of my data is in the attachment.
Anyone know how to solve it?
Thank you so much.

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dpb
2019 年 1 月 20 日
What is the fi function?
As far as column-major order, simply transpose your array to turn rows to columns.
fi function can change the storige size of the data.
But things are much much complicated than just using transpose.
Do you know how to solve my problem?

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回答者: Walter Roberson
2019 年 1 月 21 日

bits11 = uint16(x) * 128 + uint16(y) * 8 + uint16(orientatation);
However if you want to pack together the 11 bit quantities into words you would need 8 of them together, which would put together 8 such sets of data into 11 bytes. That is a bit more of a nuisance.

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