### Translated by

このページのコンテンツは英語から自動翻訳されています。自動翻訳をオフにする場合は「<a class="turn_off_mt" href="#">ここ</a>」をクリックしてください。

## How to store all the datas of a txt file in some given bits?

Jiajie Zhang

### Jiajie Zhang (view profile)

さんによって質問されました 2019 年 1 月 20 日

### Walter Roberson (view profile)

さんによって 回答されました 2019 年 1 月 21 日
I have a txt like this:
9,15,5,10,14,5,11,15,5,7,19,0,4,22,0
7,8,7,10,8,4,11,7,0,9,12,7,11,11,0
each row has 15 data values; actually it's a set of 5 points with three atrributions.
such as, the first point is (9,15,5),9 and 15 are x and y direction of a point, 5 is the orientation,
I want to use 4 bits to store x and y, 3 bits to store orientation.
and then store all the data after transformation in a new txt file.
The sample of my data is in the attachment.
Anyone know how to solve it?
Thank you so much.

dpb

### dpb (view profile)

2019 年 1 月 20 日
What is the fi function?
As far as column-major order, simply transpose your array to turn rows to columns.
Jiajie Zhang

### Jiajie Zhang (view profile)

2019 年 1 月 21 日
fi function can change the storige size of the data.
But things are much much complicated than just using transpose.
Do you know how to solve my problem?

サインイン to comment.

## 1 件の回答

### Walter Roberson (view profile)

2019 年 1 月 21 日

bits11 = uint16(x) * 128 + uint16(y) * 8 + uint16(orientatation);
However if you want to pack together the 11 bit quantities into words you would need 8 of them together, which would put together 8 such sets of data into 11 bytes. That is a bit more of a nuisance.

#### 0 件のコメント

サインイン to comment.

Translated by