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How to store all the datas of a txt file in some given bits?

Jiajie Zhang さんによって質問されました 2019 年 1 月 20 日
最新アクティビティ per isakson
さんによって 編集されました 2019 年 6 月 12 日
I have a txt like this:
9,15,5,10,14,5,11,15,5,7,19,0,4,22,0
7,8,7,10,8,4,11,7,0,9,12,7,11,11,0
each row has 15 data values; actually it's a set of 5 points with three atrributions.
such as, the first point is (9,15,5),9 and 15 are x and y direction of a point, 5 is the orientation,
I want to use 4 bits to store x and y, 3 bits to store orientation.
and then store all the data after transformation in a new txt file.
The sample of my data is in the attachment.
Anyone know how to solve it?
Thank you so much.

  2 件のコメント

dpb
2019 年 1 月 20 日
What is the fi function?
As far as column-major order, simply transpose your array to turn rows to columns.
Jiajie Zhang 2019 年 1 月 21 日
fi function can change the storige size of the data.
But things are much much complicated than just using transpose.
Do you know how to solve my problem?

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回答者: Walter Roberson
2019 年 1 月 21 日

bits11 = uint16(x) * 128 + uint16(y) * 8 + uint16(orientatation);
However if you want to pack together the 11 bit quantities into words you would need 8 of them together, which would put together 8 such sets of data into 11 bytes. That is a bit more of a nuisance.

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