Deleting certain columns in a matrix
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Hi all,
I have a 267x34 matrix. Now I want to delete certain columns within MATLAB.
For instance if I want to delete the 3rd column, 4th column, 8th column, 14th column and 33 column. How would I write this in a code where they all get delete simultaneously?
Thanks,
2 件のコメント
Mayank Malaviya
2016 年 9 月 2 日
編集済み: Mayank Malaviya
2016 年 9 月 2 日
B = horzcat(A(1:end,1:n-1),A(1:end,n+1:end)); % A is your matrix and n is the column which is to be removed
Fabian Lischka
2018 年 11 月 26 日
FWIW, above comment from 2016-09-02 does not address the question (deleting multiple columns), and is furthermore possibly a fairly inefficient way of doing what it does (deleting one column).
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Reza Zakernejad
2017 年 10 月 12 日
編集済み: Reza Zakernejad
2017 年 10 月 12 日
A(:,[m n p...])=[]; % A input matrix and m n p are #columns to be deleted
1 件のコメント
Craig Champlin
2019 年 12 月 5 日
Not sure why this is not the "Accepted Answer". It does exactly what I want to. I have several column indexes of outliers which I found by comparing against a threshold. Using this answer, I can simply put my list into the [] and poof outliers are gone.
outliers = find (errorDist > thresholdValue); % list of outliers
M(:,outliers) = []; % *poof!* clean matrix
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