How to store data in a nested for loop?

This is my skeleton Code:

c = 0
for J = 1: 1 : 12
      c = c+1;
               .
               .
               .
     for delta = 1: 1 : 10
                    .
                    .
                    .
                  A (c) =
                  B (c) =
                  C (c) =
                  D (c) =
    end
end

Here the output of A, B, C, D are (12 by 1) column vectors. In my case i can only store one 12 by 1 column vector A for delta = 10. I want to store all the A vectors for delta 1 to 10 and store side by side so that i can get a 12 by 10 matrix.

Same thing implies for B,C,D also.

How can i store the data in this pattern?

Answer 1

[madhan ravi]

A=cell(12,10); %pre-allocation for speed and efficiency
B=cell(12,10);
C=cell(12,10);
D=cell(12,10);
for J = 1:12
     for delta = 1:10
                  A{c,delta} =
                  B{c,delta} =
                  C{c,delta} =
                  D{c,delta} =
    end
end

see { } which stores the values as cell , to view the values simply do

celldisp(A)

[Mr. 206]

Hi,

See using A (c) i am piling all the A values for J loop into one column (12 by1) vector. Now for delta there are 10 such kind of column vectors (12 by 1).

I just need to pile them together to get a 12 by 10 matrix. Hope i can make my point.

[madhan ravi]

yes i understood your point see edited answer

[Mr. 206]

celldisp(A) is not giving a 12 by 10 matrix. Rather it is giving a lot of individual numbers!

[madhan ravi]

you could do

[A{:}]

also whats your formula on right hand side it should produce 12by1 elements in an iteration

[Mr. 206]

A is actually producing one number, after doing A (c) it creates a 12 by 1 column vector.

[madhan ravi]

I want to store all the A vectors for delta 1 to 10 and store side by side so that i can get a 12 by 10 matrix.

? so did you try my code?

[Mr. 206]

It creates one long column vector. It is piling all the A in one column vector

[madhan ravi]

can you provide the formula so i can try it out myself?

[Mr. 206]

I solved the problem. Thanks for your effort.

c = 0
for J = 1: 1 : 12
      c = c+1;
               .
               .
               .
     for delta = 1: 1 : 10
                    .
                    .
                    .
                  A (c,delta) =
                  B (c,delta) =
                  C (c,delta) =
                  D (c,delta) =
    end
end

[madhan ravi]

Thats exactly what my answer would also give you

[Mr. 206]

May be due to something inside my code it is not acting as expected.

To me your logic looks good. I am accpeting the Answer.

Again thanks for your help.

[madhan ravi]

Anytime :)