Create a matrix from a csv

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Lorant
Lorant 2018 年 11 月 6 日
編集済み: madhan ravi 2018 年 11 月 6 日
Hello, I have a csv file with a structure like this (or just take a look at the csv):
  1. name11,name21,name31
  2. number,number,number
  3. number,number,number
  4. ...
  5. name21,name22,name23
  6. number,number,number
  7. number,number,number
  8. ...
  9. name31,name32,name33
  10. number,number,number
  11. ...L ist the length of the space between two names, N is the number of matrixes.I want to save every number between two names as a separate matrix, the best would be a Lx3xN.How can I do that?
  4 件のコメント
Jan
Jan 2018 年 11 月 6 日
There are some blank lines in addition.
How do you want to treat the date?
5 Nov 2018 11:00:00.000,6110.403876,-1714.451633,2349.558833
This does not match the pattern "number,number,number" exactly.
Lorant
Lorant 2018 年 11 月 6 日
Yeah, that's true, I don't need the date, just the last three numbers.

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回答 (1 件)

madhan ravi
madhan ravi 2018 年 11 月 6 日
編集済み: madhan ravi 2018 年 11 月 6 日
Try
readtable()
T=readtable('Testfile_1.csv');
T(:,end-2:end) %reads last three columns

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