フィルターのクリア

comparing consecutive coordinate values in terms of X , Y and Z.

1 回表示 (過去 30 日間)
Pratik Pandya
Pratik Pandya 2018 年 11 月 6 日
コメント済み: KSSV 2018 年 11 月 7 日
I am trying to compare the consecutive values of centroid(points generated randomly : p = rand(100,3)) in all the three axes individually so as the change in values of consecutive coordinates in any particular axes value leads me to velocity in that particular axes(by using a formula to relate distance with time).Then i wish to find the acceleration from that velocity value so that i have the axis of change in acceleration as well.
Any expert guidance with a descriptive explanation would be appreciated.
  1 件のコメント
madhan ravi
madhan ravi 2018 年 11 月 6 日
upload your code and required datas and illustrate an example onto where your getting at

サインインしてコメントする。

回答 (1 件)

KSSV
KSSV 2018 年 11 月 6 日
N = 100;
P = rand(N,3) ;
% Get distances
d = pdist2(P,P) ;
[Q,idx] = sort(d(:,1)) ; % arrange points according to nearest
P = P(idx,:) ;
  15 件のコメント
Pratik Pandya
Pratik Pandya 2018 年 11 月 7 日
Let us say we have fixed starting and ending point of the path. But the intermediate points are randomly selected.Now after every time interval (can be frequency also , if it is effective), the change in each coordinate ( in terms of x or y or z) from the previous value should be compared so as to know the distance travelled and the direction as well.once we have the distance covered (and the axis where the coordinate change is observed) we have to find the velocity to show the velocity increase in that direction (x or y or z).and then i want to calculate the acceleration from the velocity values.
KSSV
KSSV 2018 年 11 月 7 日
It is simple right? If A(X1,y1,z1) point is changed to B(X2,y2,z2). Then velocity is given by:
((x2-x1)/dt,(y2-y1)/dt,(z2-z1)/dt).

サインインしてコメントする。

カテゴリ

Help Center および File ExchangeAnnotations についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by