Create a vector by selection randomly vectors

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Nikolas Spiliopoulos
Nikolas Spiliopoulos 2018 年 11 月 5 日
Hi all,
I have 4 vectors
A=[1 2 3 4 5];
B=[0 2 5 6 19];
C=[0 0 1 3 0];
D=[1 0 1 15 0];
And I want to create vectors by randomly selecting from the list above, so that I take something like:
Vector1=[B;C;D;A]
Vector2=[C;D;A;B]
Vector3=[A;D;C;B]
.
.
.
etc.

採用された回答

Stephan
Stephan 2018 年 11 月 5 日
編集済み: Stephan 2018 年 11 月 5 日
A=[1 2 3 4 5];
B=[0 2 5 6 19];
C=[0 0 1 3 0];
D=[1 0 1 15 0];
pool = [A; B; C; D];
n = 10 % Number of vectors to create
for k = 1:n
idx = randperm(4);
result(k,:) = [pool(idx(1),:), pool(idx(2),:), pool(idx(3),:), pool(idx(4),:)]
end
This code stores the created vectors in the lines of a Matrix. Access them with:
vector_1 = result(1,:)
vector_2 = result(2,:)
.
.
.
vector_n = result(n,:)
Best regards
Stephan
  1 件のコメント
Nikolas Spiliopoulos
Nikolas Spiliopoulos 2018 年 11 月 5 日
thanks a lot! it's working..!!

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その他の回答 (2 件)

Stephen23
Stephen23 2018 年 11 月 5 日
編集済み: Stephen23 2018 年 11 月 5 日
Having separate vectors is a pain to work with, so the first thing to do is to put them into one matrix M:
>> M = [1,2,3,4,5;0,2,5,6,19;0,0,1,3,0;1,0,1,15,0]
M =
1 2 3 4 5
0 2 5 6 19
0 0 1 3 0
1 0 1 15 0
>> N = 7; % how many output matrices
>> [~,R] = sort(rand(N,size(M,1)),2);
>> C = cellfun(@(r)M(r,:),num2cell(R,2),'uni',0);
>> C{:}
ans =
0 0 1 3 0
1 0 1 15 0
0 2 5 6 19
1 2 3 4 5
ans =
1 2 3 4 5
0 2 5 6 19
1 0 1 15 0
0 0 1 3 0
ans =
1 2 3 4 5
1 0 1 15 0
0 0 1 3 0
0 2 5 6 19
ans =
1 2 3 4 5
1 0 1 15 0
0 2 5 6 19
0 0 1 3 0
ans =
0 0 1 3 0
1 0 1 15 0
1 2 3 4 5
0 2 5 6 19
ans =
0 2 5 6 19
0 0 1 3 0
1 0 1 15 0
1 2 3 4 5
ans =
0 2 5 6 19
1 0 1 15 0
1 2 3 4 5
0 0 1 3 0

madhan ravi
madhan ravi 2018 年 11 月 5 日
編集済み: madhan ravi 2018 年 11 月 5 日
EDITED
A=[1 2 3 4 5]; B=[0 2 5 6 19]; C=[0 0 1 3 0]; D=[1 0 1 15 0];
vectors = [A;B;C;D];
n = 10 ; % specify n to create n number of vectors
VECTORS = cell(1,n); %PREALLOCATION
for i = 1:n
VECTORS{i}=[vectors(randsample((1:4),4) ,:)];
end
celldisp(VECTORS)
  1 件のコメント
Stephen23
Stephen23 2018 年 11 月 5 日
編集済み: Stephen23 2018 年 11 月 5 日
Note that randi can repeat values in its output array, so this answer does not match the examples given (which do not repeat any rows and are all row permutations of the same matrix).
For example:
>> randi([1,4],2,2)
ans =
1 4
1 4
Would return A,A,D,D: where are B and C ?
One solution is to use randperm, as Stephan Jung's answer shows.

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