Plotting multiple objects on same axis

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Jide Williams
Jide Williams 2018 年 10 月 26 日
コメント済み: Jide Williams 2018 年 10 月 26 日
I am new to MATLAB but I am trying to plot multiple circles on the same axis. I am using rand function to generate the centers because I want some of them to overlap, but it ends up plotting just one circle. Below is my code;
r = 0.005; x = rand(100,1); y = rand(100,1); th = 0:pi/100:2*pi; for i = 1:length(x) & 1:length(y) a = r*cos(th) + x(i); b = r*sin(th) + y(i); axis tight; hold on plot(a,b) end

採用された回答

Kevin Chng
Kevin Chng 2018 年 10 月 26 日
編集済み: Kevin Chng 2018 年 10 月 26 日
r = 0.005;
x = rand(100,1);
y = rand(100,1);
th = 0:pi/100:2*pi;
for i = 1:1:length(x)
a = r*cos(th) + x(i);
b = r*sin(th) + y(i);
figure(1)
axis tight;
hold on
plot(a,b)
pause(0.1)
end
Slight change your code, it is very interesting, if you add pause(), then you see the animation. However, you delete the pause() if you don't want it.

その他の回答 (3 件)

madhan ravi
madhan ravi 2018 年 10 月 26 日
編集済み: madhan ravi 2018 年 10 月 26 日
r = 0.005;
x = rand(100,1);
y = rand(100,1);
th = 0:pi/100:2*pi;
a=zeros(1,numel(x)) % preallocation for speed and efficiency
b= zeros(1,numel(y))
for i = 1:numel(x)
a(i) = r*cos(th(i)) + x(i);
b(i) = r*sin(th(i)) + y(i);
end
axis tight;
hold on
plot(a,b,'ob')
  7 件のコメント
jonas
jonas 2018 年 10 月 26 日
Yep, you are entirely correct in that it's a poorly written question. One of the things you learn on this forum is filling in blanks and interpreting ambiguities, which is actually quite useful when teaching :)
With that said, the notations r and the values of th (0 to 2pi) and the fact that OP accepted @Keving Chng's answer would imply that OP intended the radius to go as input.
madhan ravi
madhan ravi 2018 年 10 月 26 日
Wow thanks Jonas completely agree with you , one thing experience is gained day by day :)

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jonas
jonas 2018 年 10 月 26 日
If you have the image processing toolbox available, then there is a one-line solution to your problem.
viscircles([x,y],ones(size(x)).*r)
  6 件のコメント
jonas
jonas 2018 年 10 月 26 日
Viscircles basically does the same thing as your code, but probably more effeciently. I have not actually timed and compared.
Jide Williams
Jide Williams 2018 年 10 月 26 日
Thanks again

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Jide Williams
Jide Williams 2018 年 10 月 26 日
Ok, Thanks

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