How can we get the solution for an 'exact differential equation' dy/dx=(x^2-y^2)/2*x*y in matlab
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'exact differential equation'dy/dx=(x^2-y^2)/2*x*y'
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Star Strider
2018 年 9 月 30 日
You seem to have omitted the LHS.
dxdt = (x^2-y^2)/2*x*y
dydt = (x^2-y^2)/2*x*y
dxdy = (x^2-y^2)/2*x*y
dydx = (x^2-y^2)/2*x*y
or something else?
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