Problem using function handles

I have a homework problem where I have to code a function for a bisection root finder. One of the inputs to the function is the handle to the function to be searched, but I'm having problems implementing it. I'm gonna simplify this from my homework, but let's say I have a test function thats:
function [y] = f(x)
y = x - cos(x);
end
And my bisection root finder is:
function [root] = bisection(func, upper_bound, lower_bound)
func_ub = @func(upper_bound);
func_lb = @func(lower_bound);
root = (func_up + func_lb)/2;
end
If I enter bisection(f,0,2) in the command window matlab returns the error:
Not enough input arguments.
Error in f (line 2)
y = x - cos(x);
I'm trying to get some values for func_ub and func_lb by plugging in my upper_bound and lower_bound into my function f, some help would be greatly appreciated. Thanks!

回答 (1 件)

Rik
Rik 2018 年 9 月 29 日

2 投票

Maybe you mean this?
bisection(@f,0,2)

4 件のコメント

Jarrett Barber
Jarrett Barber 2018 年 9 月 29 日
I think you're on the right the right track, but if I enter that now I'm getting the error:
Error: File: test.m Line: 2 Column: 16
Unbalanced or unexpected parenthesis or bracket.
It's not liking the parenthesis in @func(lb).
Rik
Rik 2018 年 9 月 29 日
You don't need the @ in the bisection function
Jarrett Barber
Jarrett Barber 2018 年 9 月 29 日
That worked! Thanks so much
Rik
Rik 2018 年 9 月 29 日
You're welcome. If this solved your problem, please hit the 'accept answer' button. If not, feel free to post your remaining issues in a comment below.

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