Inverse a non-linear linspace

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unkown character
unkown character 2018 年 9 月 24 日
コメント済み: Adam Danz 2018 年 9 月 24 日
Hi,
I have the following code to get a normally distributed vector of 15 points between -20 and 20:
x_coor = linspace(-1,1,15);
mu = 0;
sigma = 0.5;
x = normcdf(x_coor, mu, sigma) ;
x = x * 40;
x = x - 20;
the output is as following:
Columns 1 through 11
-19.0900 -18.2705 -16.9375 -14.9380 -12.1727 -8.6458 -4.4981 0 4.4981 8.6458 12.1727
Columns 12 through 15
14.9380 16.9375 18.2705 19.0900
how can i invert this such that it would be something like:
-19.09 14 10 8 6 ...
so that it has more values around 0 rather than around plusminus 20?
  2 件のコメント
ANKUR KUMAR
ANKUR KUMAR 2018 年 9 月 24 日
What exactly you wish to do. Tell us in detail might helps you to get the required answer. Tell us what you are expecting the answer clearly.
Adam Danz
Adam Danz 2018 年 9 月 24 日
I agree, your goal is very unclear. Plotting x as a function of x_coor reveals a sigmoidal curve. Maybe you could describe how you'd like that sigmoid to change.

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