Trouble getting two conditions to work with array While loop

I'm having problems getting my while loop to work with two conditions. I'm trying to create an array that contains the numbers 3 and 7, randomizing the numbers again if it doesn't contain those two. Right now, I have this. Any ideas? Thanks!

        a = zeros(1,6);
        a(1,1:6) = randperm(8,6)

        i = 0;
        while (a ~= 3 & a ~= 7)
            i = i+1;
            a(1,1:6) = randperm(8,6);
        end

[madhan ravi]

can you type your required output as an example?

[Peter Lindquist]

I'm just looking for an array of 6 random numbers that includes 3 and 7. so for example, a = 8 5 3 2 7 1.

Answer 1

[Image Analyst]

Here is one way that uses a while loop:

a(1:6) = randperm(8,6)
k = 0;
maxIterations = 200; % Whatever, the failsafe
while k <= maxIterations && sum(a == 3 | a == 7) < 2
  k = k+1;
  a = randperm(8, 6);
end
a % Show in command window.

[Peter Lindquist]

This works great, thank you!