Logical operation on column of a matrix

I'm dealing with a larger problem but say I have a 5x6 matrix: A=[0 0 0 0 1 0;0 0 0 1 0 0;1 0 0 0 0 1;0 0 1 1 1 1 ;0 1 0 1 1 0]

My goal is to complete the matrix such that for each column, as soon as 1 is present, then this will be 1 until the last row.

Typically:

Result=[0 0 0 0 1 0;0 0 0 1 1 0;1 0 0 1 1 1;1 0 1 1 1 1;1 1 1 1 1 1] Any clue ? I can find the index on columns no problem, but i dont know how to move forward then

Answer 1

[Stephen23]

Here are a few methods to try:

>> A = [0,0,0,0,1,0;0,0,0,1,0,0;1,0,0,0,0,1;0,0,1,1,1,1;0,1,0,1,1,0]
A =
   0   0   0   0   1   0
   0   0   0   1   0   0
   1   0   0   0   0   1
   0   0   1   1   1   1
   0   1   0   1   1   0
>> B = +(cumsum(A,1)>0)
B =
   0   0   0   0   1   0
   0   0   0   1   1   0
   1   0   0   1   1   1
   1   0   1   1   1   1
   1   1   1   1   1   1
>> B = sign(cumsum(A,1))
B =
   0   0   0   0   1   0
   0   0   0   1   1   0
   1   0   0   1   1   1
   1   0   1   1   1   1
   1   1   1   1   1   1
>> B = +~~cumsum(A,1)
B =
   0   0   0   0   1   0
   0   0   0   1   1   0
   1   0   0   1   1   1
   1   0   1   1   1   1
   1   1   1   1   1   1

Answer 2

[cedric W]

Great, thanks a lot !