Subtraction of negative matrix element

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Michael
Michael 2018 年 8 月 12 日
コメント済み: Michael 2018 年 8 月 15 日
Hello
My data (X,Y) and I am trying to find the distance between the Y value of two points. My issue results from the negative Y value of one of the points. Concept A =1; B =-3; C= A-B; -->4 However, I keep getting an error message
% line 1 has the following values
0 0.750000000000000
0 0
0 -0.500000000000000
0 -0.750000000000000
% Subtraction method
DistX2 = minus(line1 (1,2), line (3,2));
DistX2 = (line1 (1,2) - line (3,2));
% error code
Undefined operator '-' for input arguments of type 'matlab.graphics.primitive.Line'.
Error in PlotCurve (line 50)
DistX2 = minus(line1 (1,2), line (3,2));
  1 件のコメント
Stephen23
Stephen23 2018 年 8 月 12 日
編集済み: Stephen23 2018 年 8 月 12 日
@Michael: a line object is not a numeric array. They cannot be "subtracted" in any meaningful way. You could get the Ydata values and subtract those. But most likely it would be simpler and easier to just subtract the values that you used to create the line object: so how did you create this line object?
Do NOT call your variable line, as this shadows the very important inbuilt line function.

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採用された回答

Image Analyst
Image Analyst 2018 年 8 月 12 日
line() is a built-in function and you are not using it correctly. Do not use built-in function names for names of your variables. Call it line2 or something instead of line.
  1 件のコメント
Michael
Michael 2018 年 8 月 15 日
Thanks, Yes I agree that it should be callled something else the second term should be named differently. It was supposed to have read
DistX2 = minus(line1 (1,2), line1 (3,2));
However, cut and paste plus editing resulted in it being missed and the error code just wasn't descriptive enough for me to pick out.

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