histogram function, bins and edges

14 ビュー (過去 30 日間)
Timo Strotbaum
Timo Strotbaum 2018 年 8 月 1 日
コメント済み: Adam Danz 2023 年 4 月 18 日
Hi everybody,
I´m trying to plot some histogramms of different vectors, and therefore i need to determine as well the number of bins as the Edges for the histogramm. when changing either of them, Matlab changes the other one automatically, is there a way i can determine these numbers by myself?
h = histogram(v,"NumBins",100,'Normalization','probability', "BinEdges", [5.4536e+03:1.2093e+05])
I tried to put everything in as input arguments, but the histogramm has different values:
h =
Histogram with properties:
Data: [66001×1 double]
Values: [1×115476 double]
NumBins: 115476
BinEdges: [1×115477 double]
BinWidth: 1
BinLimits: [5.4536e+03 1.2093e+05]
Normalization: 'probability'
FaceColor: 'auto'
EdgeColor: [0 0 0]
  2 件のコメント
KSSV
KSSV 2018 年 8 月 1 日
Why do you feel they are different? It is acting accordingly to your input.
Timo Strotbaum
Timo Strotbaum 2018 年 8 月 1 日
Because in said NumBins should be 100, not 115476

サインインしてコメントする。

採用された回答

KSSV
KSSV 2018 年 8 月 1 日
If you want 100 bins use:
h = histogram(v,"NumBins",100,'Normalization','probability', "BinEdges", linspace(5.4536e+03,1.2093e+05,101)) ;
  1 件のコメント
Adam Danz
Adam Danz 2023 年 4 月 18 日
In this case, "NumBins" is being ignored. Either use NumBins or BinEdges.
Here's an example where NumBins=2 but there are 100 bins defined by BinEdges.
h = histogram(rand(1,1000), "NumBins", 2, "BinEdges", linspace(0, 1, 101));

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeHistograms についてさらに検索

タグ

製品


リリース

R2018a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by