I need two decimal values without rounding off
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Hi, I have a matrix which do contain decimal values.But I need just 2 decimals without rounding off the values.For example I have a value like 0.0194.My result should be 0.01.How can I do that?
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回答 (2 件)
madhan ravi
2018 年 7 月 22 日
編集済み: madhan ravi
2018 年 7 月 23 日
Hi try this:
a=floor(100 * 0.0194)/100
fprintf('%0.2f',a)
For more clarification click the link below:
https://www.mathworks.com/matlabcentral/answers/32169-how-can-i-format-a-percent-using-2-digits-after-the-decimal
Note:floor command was taken from Sir Walter.
I recently figured out a syntax you were looking for. Try this for sure:
format bank
6 件のコメント
Image Analyst
2018 年 7 月 24 日
You mean the question about the first option being fine? Yes of course it would work - it's basically the answer I gave, before you realized your first answer with sprintf() (which gave 0.02) didn't work and changed it. And then Walter added the option of floor, which handles the rounding in a different direction for negative numbers. So, yes fix() and floor() both can work - just depends on what they want. If there are no negative numbers, it doesn't matter and you can use either fix() or floor().
"format bank" just changes how the numbers are displayed but does not actually change the number at all like fix/floor does.
Walter's last sentence is also important to understand, as is this related FAQ: https://matlab.wikia.com/wiki/FAQ#Why_is_0.3_-_0.2_-_0.1_.28or_similar.29_not_equal_to_zero.3F
Image Analyst
2018 年 7 月 22 日
Use fix:
v = 0.0194
v2 = fix(100 * v)/100
1 件のコメント
Walter Roberson
2018 年 7 月 22 日
If your value were -0.0194 and you want the answer -0.01 then fix() is the right thing to use. If you wanted -0.02 instead (the 1/100th that is less than or equal to the number) then you would use floor() instead of fix()
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