How can I polar plot in decibels?

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Pilar Jiménez
Pilar Jiménez 2018 年 7 月 11 日
コメント済み: Pilar Jiménez 2018 年 7 月 11 日
I have the following results in dBs, I need to make a polar graph with these values, but I can not find the correct way to graph them. I hope you can help me, this is the code I have:
puntos=101;
teta=linspace(-pi/2,pi/2,puntos);
corte0=[ -7.838577 -7.832224 -7.813205 -7.781625 -7.737674 -7.681614 -7.613759 -7.534502 -7.44429 -7.343629 -7.233057 -7.113168 -6.984587 -6.847963 -6.703968 -6.553286 -6.396613 -6.234628 -6.068019 -5.897437 -5.723536 -5.54693 -5.368196 -5.187878 -5.006474 -4.824449 -4.642216 -4.460145 -4.278563 -4.097766 -3.918009 -3.739528 -3.562553 -3.387297 -3.214005 -3.042917 -2.874333 -2.708591 -2.546094 -2.387311 -2.232779...
-2.083104 -1.938968 -1.801116 -1.670343 -1.547495 -1.43342 -1.328996 -1.235081 -1.152506 -1.082048 -1.024429 -0.980308 -0.950234 -0.934665 -0.933967 -0.948368 -0.978023 -1.022938 -1.083016 -1.158051 -1.247738 -1.351648 -1.469277 -1.600019 -1.743196 -1.898051 -2.06376 -2.239445 -2.424194 -2.617045 -2.816997 -3.023051 -3.234174 -3.449336 -3.667496 -3.887619 -4.108674 -4.329646 -4.549521 -4.767314 -4.982032 -5.192729...
-5.398455 -5.598276 -5.791293 -5.976641 -6.15345 -6.320908 -6.478218 -6.624628 -6.759425 -6.881949 -6.991595 -7.0878 -7.170061 -7.237973 -7.291164 -7.329369 -7.352368 -7.360037];
parche=db2mag(corte0);
corte90= [-21.7136 -21.422581 -20.646576 -19.587852 -18.420361 -17.246315 -16.113091 -15.037758 -14.023014 -13.065556 -12.159986 -11.300657 -10.482368 -9.700682 -8.951984 -8.233437 -7.54299 -6.879227 -6.241355 -5.629077 -5.042615 -4.482525 -3.949742 -3.4454 -2.970901 -2.527738 -2.117475 -1.741663 -1.401798 -1.09923 -0.835085 -0.61021 -0.425063 -0.279627 -0.173322 -0.104944 -0.072548 -0.073378 -0.10389 -0.159741...
-0.235912 -0.326925 -0.427152 -0.531135 -0.634019 -0.731884 -0.821932 -0.902473 -0.972771 -1.032644 -1.082048 -1.120685 -1.147753 -1.161962 -1.161733 -1.145631 -1.112919 -1.064068 -1.001096 -0.927695 -0.849008 -0.771236 -0.701124 -0.645415 -0.61041 -0.601672 -0.623827 -0.680485 -0.774288 -0.906942 -1.07932 -1.291582 -1.543242 -1.833276 -2.160211 -2.522179 -2.916971 -3.342113 -3.794876 -4.27235 -4.771453 -5.288964...
-5.821557 -6.365805 -6.918194 -7.475142 -8.032939 -8.58776 -9.135592 -9.672182 -10.192956 -10.692926 -11.166648 -11.608166 -12.011011 -12.368385 -12.673313 -12.919049 -13.099545 -13.209938 -13.247106];
parche90=db2mag(corte90);
polar(teta,corte0,'k')
hold on;
polar(teta,corte90)
The objective is to have a graph like this, with the labels in dBs.

採用された回答

Kelly Kearney
Kelly Kearney 2018 年 7 月 11 日
If you have a recent version of Matlab (R2016a or later), you can use polaraxes/polarplot to get much more flexibility in setting up your axis:
polaraxes('RLim', [-22 0], ...
'thetadir', 'clockwise', ...
'thetazerolocation', 'top');
hold on;
polarplot(teta, [corte0; corte90]);
If you're running an older version of Matlab, the mmpolar function (available on the File Exchange) offers very similar functionality:
mmpolar(teta, [corte0; corte90], ...
'RLimit', [-22 0], ...
'TDirection', 'cw', ...
'TZeroDirection', 'North');
Both functions allow you to customize many properties of the polar axis, including R- and Theta-limits, angle direction and units, colors, labels, etc. Polaraxes are a little more robust, in that they create modifiable handle objects, but are still pretty limited in what can be plotted (no support of patch objects, for example), so I keep both these functions in my arsenal for now.
  4 件のコメント
Kelly Kearney
Kelly Kearney 2018 年 7 月 11 日
If you're running an older version of Matlab, especially a pre-HG2 version of Matlab (graphics were overhauled in R2014b), I don't believe you'd be able to open the polarplot figure even if I sent it to you.
Looks like the File Exchange is down for maintenance today, but you should be able to download mmpolar as soon as that's back up.
Pilar Jiménez
Pilar Jiménez 2018 年 7 月 11 日
Yes, I will be waiting to download. Meanwhile, I have solved it by asking a partner to lend me his laptop with a newer version. Thank you for your help.

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その他の回答 (1 件)

dpb
dpb 2018 年 7 月 11 日
You're in luck; TMW did introduce a somewhat more capable polar plotting capability in R2016b...
hP=polarplot(teta,corte0,'k');
hold on
hP(2)=polarplot(teta,corte90);
rlim([-40 0])
It still is lacking in some features, amongst which is there is no 'RLabel' nor 'ThetaLabel' property altho there is associated 'xxxTickLabel'. Why left of the overall label is anybody's guess. Anyways, complaints aside...
hAx=gca; % returns a new polaraxis object
hTxt=text(deg2rad(82),4,'dB'); % label for the r-axis units...trial and error to locate
  1 件のコメント
Pilar Jiménez
Pilar Jiménez 2018 年 7 月 11 日
Thank you very much for the description of the new polar plotting capability, I think it is a very good tool, unfortunately I have a previous version of Matlab, I use the R2014a version. I would be very helpful if you could send me the .fig file, do you think it's possible?

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