dir([num2str(d) '\*.png']

dir([num2str(d) '\*.png']

Any one can tell me what is happening over here?

Answer 1

[Stephen23]

It searches for files name with the file extension .png that are located in the directory d.

dir([num2str(d) '\*.png']
                '\*.png'   % character vector
     num2str(d)            % convert |d| to character
    [                   ]  % horizontally concatenate the two character vectors
dir(                     ) % call DIR

Better would be to use fullfile:

dir(fullfile(num2str(d),'*.png'))

[Shanuka Jayasinghe]

errr no... i got something else utilizing that code.

for the case where d = 'string'

it searches for files in the current directory that match the file name 'string*.png'

Here's what I got in my command window when i pasted the above code with d = 'string'

>> d = 'string'

d =

'string'

>> dir([num2str(d) '\*.png'])

'string\*.png' not found.

I even tried placing a file named 'string50x.png' in the folder to test this and ended up with the same command output.

I AM trying to find out how to do what you said it did though, so if you've found out how to do that, would you mind replying here?

[Walter Roberson]

for the case where d = 'string' it searches for files in the current directory that match the file name 'string*.png'

No, it does not. Not that code. If you wanted that to happen, you would need to use '*.png' instead of '\*.png'

[Shanuka Jayasinghe]

Thanks for the reply!

I had also posted a question on reddit, and a user pointed out that i could use the strcat command.

https://www.reddit.com/r/matlab/comments/g0vjlu/loading_a_file_with_only_the_first_two_characters/

I found that example to work for my specific case, but maybe this will help someone else as well.