storing output (which are matrices) of for loops

2 ビュー (過去 30 日間)
Sumera Yamin
Sumera Yamin 2018 年 6 月 6 日
コメント済み: Sumera Yamin 2018 年 6 月 6 日
Hello, I am trying to store my output from for loop to be used later in code. The output is a 2x4 matrix for each cycle of loop. here is my code.
B= [0.0250; 0.0500; 0.0750; 0.1000; 0.1250; 0.1500; 0.1750; 0.2000; 0.2250; 0.2500; 0.2750; 0.3000; 0.3250; 0.3500; 0.3750; 0.4000];
rig=0.01
for j=1:length(B)
k= B(j)/(2*rig)
TMP= [cos(k*l)^2, (sin(k*l)*cos(k*l))/k, sin(k*l)*cos(k*l), (sin(k*l)^2)/k;
-k*sin(k*l)*cos(k*l), cos(k*l)^2, -k*sin(k*l)^2, sin(k*l)*cos(k*l);
-sin(k*l)*cos(k*l), -(sin(k*l)^2)/k, cos(k*l)^2, (sin(k*l)*cos(k*l))/k;
k*sin(k*l)^2, -sin(k*l)*cos(k*l), -k*sin(k*l)*cos(k*l), cos(k*l)^2]
TM= TMP*TMP
C1=[TM(1,:);TM(3,:)]
end
I want to store C1 and k for each cycle of loop to be used later in other parts of code. please let me know what would be the best way to do so. I tried to do it by initializing an array (like we do for scalar outputs but this did not workout. Thank you very much for your help.

採用された回答

Stephen23
Stephen23 2018 年 6 月 6 日
編集済み: Stephen23 2018 年 6 月 6 日
Array preallocation works for me:
l = 1;
B = [0.0250; 0.0500; 0.0750; 0.1000; 0.1250; 0.1500; 0.1750; 0.2000; 0.2250; 0.2500; 0.2750; 0.3000; 0.3250; 0.3500; 0.3750; 0.4000];
B = 0.025:0.025:0.4;
kV = nan(1,1,numel(B));
CM = nan(2,4,numel(B));
rig = 0.01;
for j = 1:numel(B)
k = B(j)/(2*rig);
TMP = [cos(k*l)^2, (sin(k*l)*cos(k*l))/k, sin(k*l)*cos(k*l), (sin(k*l)^2)/k;
-k*sin(k*l)*cos(k*l), cos(k*l)^2, -k*sin(k*l)^2, sin(k*l)*cos(k*l);
-sin(k*l)*cos(k*l), -(sin(k*l)^2)/k, cos(k*l)^2, (sin(k*l)*cos(k*l))/k;
k*sin(k*l)^2, -sin(k*l)*cos(k*l), -k*sin(k*l)*cos(k*l), cos(k*l)^2];
TMP = TMP*TMP;
CM(:,:,j) = [TMP(1,:);TMP(3,:)];
kV(j) = k;
end
  1 件のコメント
Sumera Yamin
Sumera Yamin 2018 年 6 月 6 日
Thank you very much for your help

サインインしてコメントする。

その他の回答 (1 件)

Ankita Bansal
Ankita Bansal 2018 年 6 月 6 日
編集済み: Ankita Bansal 2018 年 6 月 6 日
Hi Sumera, you can do so by changing k to k(j) and C1 to C1(:,:,j).
B= [0.0250; 0.0500; 0.0750; 0.1000; 0.1250; 0.1500; 0.1750; 0.2000; 0.2250; 0.2500; 0.2750; 0.3000; 0.3250; 0.3500; 0.3750; 0.4000];
rig=0.01
for j=1:length(B)
k_1(j)= B(j)/(2*rig)
k=k_1(j);
TMP= [cos(k*l)^2, (sin(k*l)*cos(k*l))/k, sin(k*l)*cos(k*l), (sin(k*l)^2)/k;
-k*sin(k*l)*cos(k*l), cos(k*l)^2, -k*sin(k*l)^2, sin(k*l)*cos(k*l);
-sin(k*l)*cos(k*l), -(sin(k*l)^2)/k, cos(k*l)^2, (sin(k*l)*cos(k*l))/k;
k*sin(k*l)^2, -sin(k*l)*cos(k*l), -k*sin(k*l)*cos(k*l), cos(k*l)^2]
TM= TMP*TMP
C1(:,:,j)=[TM(1,:);TM(3,:)]
end
Here i have stored values in k_1.
Hope this helps.
  2 件のコメント
Stephen23
Stephen23 2018 年 6 月 6 日
Note that this does not preallcoate the output arrays, so will require the arrays to be resized and moved on each iteration.
Sumera Yamin
Sumera Yamin 2018 年 6 月 6 日
Thank you Ankita for your time and answer. This gives me good idea of my problem.

サインインしてコメントする。

カテゴリ

Help Center および File ExchangeLoops and Conditional Statements についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by