Help displaying a formatted matrix to the command window
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Hi all, this seems like a simple question, but sprintf(...) doesn't do the trick. Is there an EASY way to display a matrix in the command window with a specified number of digits of precision?
EXAMPLE:
>> x = rand(3,2) - 0.5
x =
-0.3810 -0.1596
-0.0016 0.0853
0.4597 -0.2762
>> format long >> x
x =
-0.381002318441623 -0.159614273333867
-0.001635948017857 0.085267750979777
0.459743958516081 -0.276188060508863
How do I show x with, say, 6 digits of precision (as in below)??
-0.381002 -0.159614
-0.001635 0.085267
0.459743 -0.276188
I'm sure one could write a code that figured out the size of x and then used sprintf to create the desired output. Does this code exist?
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その他の回答 (2 件)
Oleg Komarov
2012 年 6 月 5 日
sprintf('%.6f %.6f\n',rand(3,2))
Edited
Now, if you wanna make the number of columns adjust automatically, then:
A = randn(3,9);
sprintf([repmat('%10.6f',1,size(A,2)) '\n'],A)
Unfortunately, there's some learning curve in format customization.
7 件のコメント
Brenden Epps
2012 年 6 月 5 日
Oleg Komarov
2012 年 6 月 5 日
I edited the second solution, now it's correct.
Brenden Epps
2012 年 6 月 6 日
Oleg Komarov
2012 年 6 月 6 日
A = randn(3,9);
sprintf([repmat('%10.6f',1,size(A,2)) '\n'],A)
Have you tried it?
You can tweak the %10 to give more space between the numbers.
Jan
2012 年 6 月 6 日
+1: I still prefer the REPMAT approach. And if the minus character matters, I'd use the '+' specification and replace the '+' by spaces:
A = 1 - randn(3,9); fprintf(strrep(sprintf([repmat('%+10.6f',1,size(A,2)) '\n'],A), '+', ' '));
Anton
2018 年 10 月 10 日
It seems that this one transposes my matrix in the process though
@Anton: yes, all of the above examples should transpose the array, like this:
fprintf(...,A.')
The fprintf help explains that it "...applies the formatSpec to all elements of arrays A1,... An in column order, and writes the data..." (emphasis added).
Walter Roberson
2018 年 10 月 10 日
Try
num2str(x, 6)
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