Combine 2 char vectors

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Nicolas Baduel
Nicolas Baduel 2018 年 5 月 28 日
回答済み: Stephen23 2018 年 5 月 29 日
Hi everyone, Here are two vectors :
A='IMDOINGATEST'
B='ABCDE'
I would like to get this : (a regular mix)
C='IAMBDCODIENAGBACTDEESATB'
Note that A can be smaller than B but A won't repeat in B. Only B repeats in A.
Thank you !

採用された回答

Ameer Hamza
Ameer Hamza 2018 年 5 月 28 日
This will mix them as described in question
C = repmat(' ', 1, 2*numel(A))
C(1:2:end) = A;
C(2:2:end) = [repmat(B, 1, floor(numel(A)/numel(B))) B(1:rem(numel(A), numel(B)))];
For example,
A='IMDOINGATEST'
B='ABCDE'
will produce
C =
'IAMBDCODIENAGBACTDEESATB'
and
A='IMDO'
B='ABCDE'
will mix to form
C =
'IAMBDCOD' % no repetition of A
  2 件のコメント
Nicolas Baduel
Nicolas Baduel 2018 年 5 月 28 日
I will try this tomorrow, thank you for the answer !
Ameer Hamza
Ameer Hamza 2018 年 5 月 29 日
You are welcome.

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その他の回答 (1 件)

Stephen23
Stephen23 2018 年 5 月 29 日
A slightly different approach:
>> A = 'IMDOINGATEST';
>> B = 'ABCDE';
>> C = repmat(B,1,ceil(numel(A)/numel(B)));
>> C = reshape([A;C(1:numel(A))],1,[])
C = IAMBDCODIENAGBACTDEESATB
Or
>> A = 'IMDO';
>> B = 'ABCDE';
>> C = repmat(B,1,ceil(numel(A)/numel(B)));
>> C = reshape([A;C(1:numel(A))],1,[])
C = IAMBDCOD

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