Creating a matrix whose entries are matrix
1 回表示 (過去 30 日間)
古いコメントを表示
Given a matrix
A = [-4 1 0; 1 -4 1; 0 1 -4];
I want to create a matrix B such that
B = [A I 0; I B I; 0 I B];
where I is identity matrix whose size is equal to size of A. How can I do this?
0 件のコメント
採用された回答
Stephen23
2018 年 5 月 25 日
編集済み: Stephen23
2018 年 5 月 25 日
>> A = [-4 1 0; 1 -4 1; 0 1 -4];
>> I = eye(size(A));
>> Z = zeros(size(A));
>> B = [A I Z; I A I; Z I A]
B =
-4 1 0 1 0 0 0 0 0
1 -4 1 0 1 0 0 0 0
0 1 -4 0 0 1 0 0 0
1 0 0 -4 1 0 1 0 0
0 1 0 1 -4 1 0 1 0
0 0 1 0 1 -4 0 0 1
0 0 0 1 0 0 -4 1 0
0 0 0 0 1 0 1 -4 1
0 0 0 0 0 1 0 1 -4
その他の回答 (1 件)
Ameer Hamza
2018 年 5 月 25 日
I am assuming the in your question, you wrote B by mistake on the Left side of the 2nds statement and they are actually matrix A. If you want to create a big matrix B then follow @Stephen's answer. But If you want them to remain as separate matrices, then you will need a cell array
B = {A I Z; I A I; Z I A};
B =
3×3 cell array
{3×3 double} {3×3 double} {3×3 double}
{3×3 double} {3×3 double} {3×3 double}
{3×3 double} {3×3 double} {3×3 double}
Access each matrix using curly bracket notation. B{1, 2} will access matrix in the first row and second column.
参考
製品
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!