Explanation of num2str(x) - '0'
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Hi, for my homework I had to split a binary number into it's individual parts. After some tying and research I found out that I can use:
num2str(x) -'0'
I now know that it works but I don't know how it works. Can someone explain it to me?
Thanks in advance.
Marvin
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採用された回答
Ameer Hamza
2018 年 5 月 7 日
It works because num2str convert the number into a char array. For example
x = 10001100;
y = num2str(x)
ans =
'10001100'
In computer memory, each character is stored on the basis of its ASCII value. From ASCII table character '1' = 49 (decimal) and '0' = 48 (decimal). Therefore in computer memory y is saved as
y = [49 48 48 48 49 49 48 48]
now when you subtracted '0' = 48 decimal, what you are doing is
[49 48 48 48 49 49 48 48] - 48
which gives you
[1 0 0 0 1 1 0 0]
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その他の回答 (2 件)
Star Strider
2018 年 5 月 7 日
Character arrays exist as ASCII or other numeric encodings, so that each letter or other character is assigned a numeric value. In MATLAB, they are then handled as any other numeric array.
So:
zerochar = double('0')
chars = '12345'
numarray1 = double(chars)
numarray2 = numarray1 - zerochar
expands to:
zerochar =
48
chars =
'12345'
numarray1 =
49 50 51 52 53
numarray2 =
1 2 3 4 5
0 件のコメント
David Fletcher
2018 年 5 月 7 日
編集済み: David Fletcher
2018 年 5 月 7 日
num2str(x) - this converts the number to a string
Once converted subtracting '0' subtracts the character code for 0 from all entries. Therefore all zero characters become the actual value of 0, and all one characters become the actual value of 1 (since the ASCII code for '1' is one greater than the ASCII code for '0'). Subtracting 48 (the ascii code for '0' achieves the same thing).
>> '0' - 48
ans =
0
>> '1' -48
ans =
1
1 件のコメント
Stephen23
2018 年 5 月 7 日
"num2str(x) - this converts the number to a string"
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