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Fitting a plane through a 3D point data

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ha ha
ha ha 2018 年 5 月 6 日
編集済み: Matt J 2018 年 5 月 6 日
For example, i have 3d point cloud data [xi, yi, zi] as the attachment .txt file. I want to fit a plane to a set of 3D point data. What kind of method to do that?
  1 件のコメント
Matt J
Matt J 2018 年 5 月 6 日
How does one know that M and L are different planes and not just noise? Is there a known upper bound on the noise? A known lower bound on the separation distance between M and L?

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採用された回答

Matt J
Matt J 2018 年 5 月 6 日
You will probably have to implement a RANSAC plane fitting routine.
  5 件のコメント
ha ha
ha ha 2018 年 5 月 6 日
Thanks.
Matt J
Matt J 2018 年 5 月 6 日
編集済み: Matt J 2018 年 5 月 6 日
One approach you might consider is to take planar cross sections of your data. This will give 2D data for a line, with outliers. Then you can apply a ready-made RANSAC line-fitter, like the one I linked you to. From line fits in two or more cross-secting planes you should be able to construct the desired plane K.

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その他の回答 (2 件)

Walter Roberson
Walter Roberson 2018 年 5 月 6 日
data = load('1.txt');
coeffs = [data(:,1:2), ones(size(data,1),1)]\data(:,3);
The equation of the plane is then coeffs(1)*x + coeffs(2)*y - coeffs(3) = z
  1 件のコメント
ha ha
ha ha 2018 年 5 月 6 日
編集済み: ha ha 2018 年 5 月 6 日
From your answer, I plot the surface as below image. But That plane is not same as my expected plane. If we use the formulas as your proposed method, the plane is fitting through all points & will be slightly different with my expected plane K(=plane M)

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Matt J
Matt J 2018 年 5 月 6 日
編集済み: Matt J 2018 年 5 月 6 日
xyz=load('1.txt');
xyz(xyz(:,2)>40, :)=[];
mu=mean(xyz,1);
[~,~,V]=svd(xyz-mu,0);
normal=V(:,end).';
d=normal*mu';
The equation of the plane is then xyz*normal.' = d
  3 件のコメント
ha ha
ha ha 2018 年 5 月 6 日
In my question: Plane M contains a large number of point data when compared with plane L(i.e., 90%). I wanna find the plane can cover large number points as plane M. Example: in the general, there are some outlier(or noise) points. So, the result will be affected significantly. Because you are using "least square regression method" as I guessed
Matt J
Matt J 2018 年 5 月 6 日
How does one know that M and L are different planes and not just noise? Is there a known upper bound on the noise? A known lower bound on the separation distance between M and L?

サインインしてコメントする。

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