check the index of cell which were removed

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ha ha
ha ha 2018 年 3 月 6 日
編集済み: Stephen23 2018 年 3 月 6 日
Let's say:
A : 4x1 cell class
A={cell_1 ;cell_2 ; cell_3 ;cell_4 }
A={ [] ;[999,222];[444,222,2000]; [] };
B is index matrix of cell A:
B=[1;2;3;4] %index matrix of cell A
If I wanna remove the "empty cell" out of A, I can use this code:
A_remove=A(~cellfun('isempty',A));
And with respect to A, the index matrix B will be:
B_remove=[2;3]; %remove the index of "empty cell"
How can to find "B_remove" matrix from A &B ??

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Stephen23
Stephen23 2018 年 3 月 6 日
編集済み: Stephen23 2018 年 3 月 6 日
Using logical indices:
B_remove = cellfun('isempty',A)
B_keep = ~B_remove
If you really want the subscript indices then use find.
  2 件のコメント
ha ha
ha ha 2018 年 3 月 6 日
編集済み: ha ha 2018 年 3 月 6 日
My question mean: " I want to find the index matric where the cell is not empty". If i use your code:
cellfun('isempty',A)
The result is: 4x1 logical. That is I don't want to see
I hope my index matrix will be : [2;3]=result
Stephen23
Stephen23 2018 年 3 月 6 日
編集済み: Stephen23 2018 年 3 月 6 日
As my answer told you:
find(~cellfun('isempty',A))
If you can use them then logical indices are more efficient.

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