How can I use regexp to return a list of variable names?
15 ビュー (過去 30 日間)
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I want to extract variable names from a string. For my purposes, variables start with a letter or an underscore, and they end before anything except for open parenthesis ("(").
So
'sin(var1) + var2'
should become something like
["var1" "var2"]
I tried this:
testStr = 'sin(var1) + var2';
vars = regexp(testStr,'([a-zA-Z_]\w*)(?:[^(\w]|$)','tokens')
and got this:
ans =
0x0 empty cell array
What am I doing wrong?
3 件のコメント
Stephen23
2018 年 2 月 23 日
編集済み: Stephen23
2018 年 2 月 23 日
func meeets these three condidrions:
- "begins with either an English letter or an underscore" yes!
- "contains any number of English letters, underscores, and digits" yes!
- "ends before something that is not an English letter, underscore, or digit" yes!
So why is func not on your list of variables when it meets all of your conditions?
Note that the regular expression you defined on regex101 actually uses "ends before something that is not an English letter, underscore, digit, or open bracket".
回答 (2 件)
Ji Huang
2018 年 2 月 23 日
編集済み: Ji Huang
2018 年 2 月 23 日
I would do it in two steps. First, remove the functions. i.e. characters before open parenthesis
testStr = 'sin(var1) + var2';
var_step_1 = regexprep(testStr,'[\w_]{0,}\(', '\(')
It gives "(var1) + var2". Then, match vars.
var_step_2 = regexp(var_step_1,'[\w_]{0,}', 'match')
0 件のコメント
Stephen23
2018 年 2 月 23 日
編集済み: Stephen23
2018 年 2 月 23 日
>> str = 'var1 * _var2 * 2var3 + func(var5))';
>> C = regexpi(str,'([A-Z_]\w*)(?![\(\w])','match');
>> C{:}
ans = var1
ans = _var2
ans = var3
ans = var5
If you want to develop regular expressions then you might be interested in downloading my simple Interactive Regular Expression tool:
0 件のコメント
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