Trying to flip image without using the built in function

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panacean
panacean 2018 年 2 月 8 日
回答済み: shivam singh 2019 年 7 月 30 日
Trying to write a function that reads in an image and then flips the image so that its appearance is a mirror image of the original image. Here is my code for my attempt. Not quite working, if has anyone could provide some suggestions, it would be appreciated.

採用された回答

Stephen23
Stephen23 2018 年 2 月 8 日
function B = myflipped_image_lr()
A = imread('horse.jpg');
figure(1)
imshow(A);
B = A(:,end:-1:1,:);
figure(2)
imshow(B);
end
  2 件のコメント
panacean
panacean 2018 年 2 月 8 日
Just for my own understanding, could you explain how B = A(:,end:-1:1,:); is flipping the image. I confused about the logic. Thanks
Walter Roberson
Walter Roberson 2018 年 2 月 8 日
For example if there were 5 columns, then end would be 5, and end:-1:1 would be 5:-1:1 which would be [5 4 3 2 1]. The code would then be equivalent to A(:, [5 4 3 2 1], :) which extracts the data with the columns in reverse order.
Historically, fliplr() used exactly this logic of end:-1:1 (but has a different internal implementation now, calling a built-in routine)

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その他の回答 (2 件)

Image Analyst
Image Analyst 2018 年 2 月 8 日
Hint:
Replace
[ii, jj] = size(A);
with
[ii, jj, numberOfColorChannels] = size(A);

shivam singh
shivam singh 2019 年 7 月 30 日
% To create the mirror image of an image without using pre defined function
clc;
clear all;
close all;
A = imread('C:\Users\Student\Desktop\shivam_1069.jpg');
subplot(2,2,1);
imshow(A);
B = A(:,end:-1:1,:);
subplot(2,2,2);
imshow(B);

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