Circular region in an image

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Sordin
Sordin 2018 年 1 月 15 日
コメント済み: Image Analyst 2018 年 7 月 18 日
I am trying to replace a circular region in one image with the corresponding region in another image. Here is my code so far:
% Sample images:
I=imread('office_1.jpg');
I2=imread('office_5.jpg');
[imageSizeY, imageSizeX,z1] = size(I);
centerX = ceil(imageSizeX/2);
centerY = ceil(imageSizeY/2);
radius = 200;
for i=1:max(imageSizeY,imageSizeX)
if (((centerY+i) - centerY).^2 ...
+ ((centerX+i) - centerX).^2 <= radius.^2)
I(centerY:centerY+i, centerX:centerX+i, :) ...
= I2(centerY:centerY+i, centerX:centerX+i, :);
end
end
imshow(I)
Unfortunately, my code does not work correctly, and instead of a circle the result is a square (corresponding to only one quadrant of the desired circle):
What are the mistakes here? Any explanation is greatly appreciated.

採用された回答

Matt J
Matt J 2018 年 1 月 15 日
編集済み: Matt J 2018 年 1 月 15 日
I don't really follow the logic of your code, but in any case there are much simpler and more efficient approaches, e.g.,
[yy,xx,~]=ndgrid( (1:imageSizeY)-centerY, (1:imageSizeX)-centerX ,1:z1);
map=(yy.^2+xx.^2<=radius^2);
I(map)=I2(map);
  3 件のコメント
Image Analyst
Image Analyst 2018 年 1 月 16 日
編集済み: Image Analyst 2018 年 1 月 16 日
Does this work for his color image?
Sordin
Sordin 2018 年 1 月 16 日
Hi Image Analyst, Yes this worked for the color images as well.

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その他の回答 (2 件)

Image Analyst
Image Analyst 2018 年 1 月 15 日
See my attached copy and paste demos.

Prince Masedi
Prince Masedi 2018 年 7 月 18 日
II. Determine the following statistical parameter using Matlab program (Note you must copy and paste your code on the answer booklet. (1. Error variance, 2. Assume X=Rainfall Y=Runoff fill in the table with respective determined square of (X-Xm) where Xm is the mean of X and determine estimated Y termed as Yest.
  1 件のコメント
Image Analyst
Image Analyst 2018 年 7 月 18 日
How does this answer the original question about pasting circular regions into an image?

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