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Keeping a zero after a decimal

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Andre Dixon
Andre Dixon 2017 年 12 月 6 日
コメント済み: Stephen23 2023 年 2 月 14 日
Hi! I'm relatively new to MATLAB and am trying to round the values within this column vector to three significant digits. This has worked fine except for the second entry, which fails to keep a zero after the decimal point when rounded. If I have a vector: A = [27.372; 24.966; 28.908; 29.205; 23.783; 27.256], no matter whether I use: result = round(A, 3, 'significant') or result = round(A, 1), both produce the following: 27.4; 25; 28.9; 29.2; 23.8; 27.3. I would like the second row to be 25.0. Any help is much appreciated! Cheers :)
  7 件のコメント
Kurt
Kurt 2023 年 2 月 13 日
編集済み: Kurt 2023 年 2 月 13 日
A = [27.372; 24.966; 28.908; 29.205; 23.783; 27.256]
A = 6×1
27.3720 24.9660 28.9080 29.2050 23.7830 27.2560
display(sprintf('%0.1f\n',round(A,1)));
27.4 25.0 28.9 29.2 23.8 27.3
Stephen23
Stephen23 2023 年 2 月 14 日
@Kurt: SPRINTF() also performs rounding, so the separate ROUND() call is not required:
A = [27.372; 24.966; 28.908; 29.205; 23.783; 27.256];
fprintf('%0.1f\n',A)
27.4 25.0 28.9 29.2 23.8 27.3

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回答 (1 件)

Christopher Coello
Christopher Coello 2018 年 2 月 7 日
編集済み: Christopher Coello 2018 年 2 月 7 日
Well not sure about the question. But if what you want is display the vector with trailing zero then you can use the undocumented sprintfc command
A = [27.372; 24.966; 28.908; 29.205; 23.783; 27.256];
% with one decimal digit
sprintfc('%0.1f',A)
% with two decimal digits
sprintfc('%0.2f',A)
% with five decimal digits
sprintfc('%0.5f',A)
  6 件のコメント
Christopher Coello
Christopher Coello 2018 年 2 月 7 日
Nice, I like compose ! Thanks Guillaume, I'll definitely drop sprintfc now
Elysi Cochin
Elysi Cochin 2022 年 10 月 14 日
Thanks @Guillaume

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