How can I plot several graphs with slightly different name in a loop?
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I want to plot many graphs in a loop. But every plot should get a description like h1, h2 and so on, that I can change the settings after plotting all the data. How does this work? I have a read a lot that I need an array, but what do I have to change at the fourth line (names(i))?
x = {'2';'3';'4'};
names = [strcat('h',x)]
for i=[2,3,4]
names(i)=plot(xx,yy);
end
set(h2,'Linewidth',1.5);
1 件のコメント
Stephen23
2017 年 10 月 17 日
編集済み: Stephen23
2017 年 10 月 17 日
"But every plot should get a description like h1, h2 and so on, that I can change the settings after plotting all the data."
No, they definitely shouldn't have lots of names like that! That would be about the worst way to write MATLAB code: slow, buggy, complex, hard to debug, insecure. Read this to know why:
All you need is to use indexing, which is simple and efficient, and is introduced very clearly in MATLAB's Getting Started tutorials (and which are highly recommended for all beginners):
採用された回答
Rik
2017 年 10 月 17 日
You were looking for eval. Stephen Cobeldick is very pasionate about this topic (and with good reason), so I have taken the liberty of adapting some of his thoughts on this topic: Introspective programming ( eval and other functions like it) is slow, and the MATLAB documentation warns specifically against it. Using eval is slow, makes debugging difficult, and removes all code helper tools (code checking, syntax hints, code completion, variable highlighting, etc.). A longer discussion can be found here. If you are not an expert and you think you need eval, there are probably better solutions to your problem.
The code below should solve your problem.
x = [2,3,4];
names = sprintfc('h%d',x);
h=zeros(size(names));
for i=[2,3,4]
yy=rand(1,10);xx=1:10;
h(i)=plot(xx,yy);hold on
end
set(h(2),'Linewidth',1.5);
legend(h(x),names)
3 件のコメント
Rik
2017 年 10 月 17 日
sprintfc works in a similar way as sprinft, so that string is the formatspec. You can look at the documentation (type doc sprintf) to see the full range of options.
その他の回答 (3 件)
Stephen23
2017 年 10 月 17 日
編集済み: Stephen23
2017 年 10 月 17 日
How MATLAB works is different to what you are attempting: you simply allocate values into the array using indexing, rather than creating an array of names and somehow magically allocating to them.
All you need is to use indexing:
lhnd = zeros(1,4);
for k = 1:4
lhnd(k) = plot(xx,yy);
end
set(lhnd(2),'Linewidth',1.5); % use indexing!
2 件のコメント
goerk
2017 年 10 月 17 日
You can use the eval command. Simple example:
eval(['h=plot([1:10])'])
In your case something like
eval(['h' num2str(i) '= plot(xx,yy)'])
should do the job.
1 件のコメント
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