# creating matrix w.r.t. rows number of another matrix

4 ビュー (過去 30 日間)
sermet 2017 年 9 月 6 日
コメント済み: Stephen 2017 年 9 月 7 日
data=[1;2;8;9;11;12;19;22;24;26;30];
col_row=[1 2;1 4;1 8;1 11;2 4;2 8;2 11;3 10];
rows number in col_row are always ascending order. I need to store result_i matrix w.r.t. data and rows value of col_row matrix as follows.
result_1=[data(2);data(4);data(8);data(11)];
result_2=[data(4);data(8);data(11)];
result_3=data(10);
rows number in col_row always starts with 1. I need to extract second column values of each repeated numbers (1-2) and single number in col_row matrix and create result_i matrix.
Above data is example, actual data matrix is bigger and the maximum row value of col_row matrix is variable. How can I write a code to store result_i matrix?
##### 2 件のコメント表示非表示 1 件の古いコメント
Stephen 2017 年 9 月 7 日
"I need to ... and create result_i matrix"
Do not do this. It will make your code complex, slow, buggy, hard to debug, and obfuscated. Read this to know why creating or accessing variable names dynamically is a bad idea:
Indexing is simple, efficient, neat, easy to debug, and easy to understand: you should use indexing with some kind of array: a matrix, or an ND array, or a cell array, or a structure, or a table, or....

サインインしてコメントする。

### 採用された回答

James Tursa 2017 年 9 月 6 日

E.g., a method using a cell array
u = unique(col_row(:,1));
n = numel(u);
result = cell(max(u),1);
for k=1:n
result{u(k)} = data(col_row(col_row(:,1)==u(k),2));
end
This assumes that all of the "row" numbers are positive integers. If they are not, then one could do this instead
u = unique(col_row(:,1));
n = numel(u);
result = cell(n,1);
for k=1:n
result{k} = data(col_row(col_row(:,1)==u(k),2));
end

サインインしてコメントする。

### Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!