Subtracting Row and column vectors
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I need to subtract vectors of different dimensions, "A" with dimension of (1x91)double and "B" with dimension of (60x1) double. In addition, there are two more vectors "C" with dimension of (1x119) double and "D" with dimension of (119x1) double.
How can I get (X=A-B) and (Y=C-D) in such cases?
2 件のコメント
Akira Agata
2017 年 8 月 13 日
What do you mean by 'X=A-B'?
X(1) = A(1) - B(1), ..., X(60) = A(60) - B(60) ?
If so, what about X(61) to X(91) ?
I need the detailed definition of your calculation rule of 'A-B' and 'C-D'.
回答 (2 件)
Stephen23
2017 年 8 月 13 日
編集済み: Stephen23
2017 年 8 月 13 日
One simple solution that does not require knowing anything about the sizes of the vectors:
>> A = randi(9,1,9)
A =
1 3 4 3 2 8 4 8 4
>> B = randi(9,6,1)
B =
7
4
8
7
4
2
>> C = diag(bsxfun(@minus,A,B))
ans =
-6
-1
-4
-4
-2
6
For newer MATLAB versions with implicit expansion:
diag(A-B)
Note that this is not particularly memory efficient so don't use this with large vectors!
0 件のコメント
Akira Agata
2017 年 8 月 17 日
I think the following would be one possible solution. By using zero-padding and transpose, I have adjusted A and B, C and D, to the same size.
%%Example of your data
A = rand(1,91);
B = rand(60,1);
% Adjut B to a row vector with the same length with A by zero padding
B1 = [B',zeros(1, length(A) - length(B))];
% Calculate X = A - B
X = A - B1;
%%Example of your data
C = rand(1,119);
D = rand(119,1);
% Adjust D to a row vector with the same length with C
D1 = D';
% Calculate Y = C - D
Y = C - D1;
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