fzero of vector with a loop

I'm trying to find the s vector that will gave me the value of ValorMercado=ValorMercadonovo.

This is my code:

Price=[99.23;100.05;91;107.71;104.1];
cashflows=[3441 3441 301720.5;68750 1068750 0;170040 13085020 0;229350 229350 5729350;34194000 0 0];
NominalValue=[300000;1000000;13000000;5500000;32800000];
eiopa=[-0.00302;-0.00261;-0.00208];

[c3,r3]=size(Price);
[c4,r4]=size(cashflows);
ValorMercado(1:c3,1)=Price(1:c3,1).* NominalValue(1:c3,1) ./100;

s=transpose(sym ('s',[1 c3]));
S=sym(zeros(c3,1));

for i=1:c3
    ValorMercadonovo(i,1)(S)=0;
    for j=1:r4
        ValorMercadonovo(i,1)(S)=(ValorMercadonovo(i,1)/((1+eiopa(j,1)+S(i,1))^j))+(cashflows(i,j)/((1+eiopa(j,1)+S(i,1))^j));
    end
end

for i=1:c3
    x(i,1)=fzero(@(S)ValorMercado(i,1) - ValorMercadonovo(S)(i,1),[0,1]);
end

the error is Error: ()-indexing must appear last in an index expression.. What is wrong?

[Alan Weiss]

Please correct the error in your displayed code so that we can see what the issue might be. As Matt J said, the current question has an obvious syntax error, and we cannot proceed.

Alan Weiss

MATLAB mathematical toolbox documentation

Answer 1

[Matt J]

The expression

   ValorMercado(S)(i,1)

doesn't make sense. ValorMercado is a numeric vector, so can only be indexed with one pair of ()

[Mariana Ferreira]

It was there by lapse. Already fixed but its not working anyway. Could you help please?

[Matt J]

No, we need to know what the new error messages are. Also, I still see

ValorMercadonovo(i,1)(S)

What is it supposed to mean?