How to get minimum value among more than two matrix

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Vishal Sharma
Vishal Sharma 2017 年 6 月 20 日
編集済み: Jan 2017 年 6 月 20 日
I have 5 matrix of following values as per below:--
A = [1 2 3;0 0 5]
B = [3 2 3;0 0 3]
C = [1 5 3;0 0 2]
D = [7 2 3;0 0 1]
E = [4 2 3;0 0 7]
I want to find minimum value in the last row (i.e. second row) and its index also, so that the final result should be as follows:--
Minimum value = 1
Index = D(2,3)
Also, please tell how to find matrix having closest to particular value, say 3 in second row among A, B, C, D, E matrix's... So, as to get the result as per below:--
Value = 3
Matrix = B(2,3)
  3 件のコメント
Stephen23
Stephen23 2017 年 6 月 20 日
"I have 5 matrix ..."
Well, that is the problem right there. If you simply put all of your data into one array then this task would be trivially simple. Put all of your data into lots of separate arrays and you waste your life trying to figure out solutions to problems instead.
Solution: concatenate your data into one array. Then use min.
Adam
Adam 2017 年 6 月 20 日
As an aside, there are many 0s in the last row of each of those matrices so these would be the minimum values.

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回答 (1 件)

Jan
Jan 2017 年 6 月 20 日
編集済み: Jan 2017 年 6 月 20 日
Do not store the arrays in different variables, but as an array:
A = [1 2 3;0 0 5]
B = [3 2 3;0 0 3]
C = [1 5 3;0 0 2]
D = [7 2 3;0 0 1]
E = [4 2 3;0 0 7]
Data = {A,B,C,D,E};
Now run a loop:
minValue = Inf;
minIndex = 0;
minArg = 0;
for k = 1:numel(Data)
[aMin, aIndex] = min(Data{k}(2, :));
if aMin < minValue
minValue = aMin;
minIndex = aIndex;
minArg = k;
end
end
Well, a numerical array would be much easier.

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