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Sort matrix by datenum

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David du Preez
David du Preez 2017 年 5 月 9 日
回答済み: Peter Perkins 2017 年 5 月 9 日
I have a 88416 x 13 matrix. Column 1 contains the datenum values. I want to sort the matrix by column 1 keeping the corresponding values. It must be sorted from oldest to newest and keep the corresponding values

採用された回答

Stephen23
Stephen23 2017 年 5 月 9 日
編集済み: Stephen23 2017 年 5 月 9 日
Where M is your matrix, use sortrows and its second optional argument to select the column:
sortrows(M,1)

その他の回答 (1 件)

Peter Perkins
Peter Perkins 2017 年 5 月 9 日
If using MATLAB R2016b or newer, you might consider using a timetable. There are lots of benefits beyond simple sorting by time, but here's how you'd do that:
>> tt = timetable(datetime(2017,5,[1;3;2;5;4]),randn(5,1),randn(5,1),randn(5,1))
tt =
5×3 timetable
Time Var1 Var2 Var3
___________ ________ ________ _________
01-May-2017 -0.1469 -0.60006 0.96697
03-May-2017 -0.85955 -0.78089 -0.075429
02-May-2017 0.69933 -0.74781 -0.58065
05-May-2017 0.94991 0.62544 1.3161
04-May-2017 0.41305 -1.3237 1.2532
>> sortrows(tt)
ans =
5×3 timetable
Time Var1 Var2 Var3
___________ ________ ________ _________
01-May-2017 -0.1469 -0.60006 0.96697
02-May-2017 0.69933 -0.74781 -0.58065
03-May-2017 -0.85955 -0.78089 -0.075429
04-May-2017 0.41305 -1.3237 1.2532
05-May-2017 0.94991 0.62544 1.3161
Prior to R2016b, you could also use a table that contains a datetime variable. sortrows would also work on that.

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