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Using repelem without prior knowledge of the number of matrix dimensions

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Emmanouil
Emmanouil 2017 年 2 月 6 日
編集済み: Stephen23 2017 年 2 月 6 日
Hello,
I have a matrix A that can be either 3D, 4D, 5D etc. I want to repeat the elements of the last dimension x times. This can be accomplished by using the following expressions: repelem(A,1,1,x) for 3D and repelem(A,1,1,1,x) for 4D matrices. However, since I do not know the number of matrix dimensions in advance, these expressions do not help me. Ideally, I would like to use repelem like repmat e.g. repelem(A,[1,1,x]) for 3D and repelem(A,[1,1,1,x]) for 4D matrices. However these expressions are not valid. I know I can do this combining reshape and repmat but I would like to know if there is a more compact way since there is a repelem function (I would also like to avoid using eval). Any ideas?

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Stephen23
Stephen23 2017 年 2 月 6 日
編集済み: Stephen23 2017 年 2 月 6 日
It is easy to generate a comma separated list from a cell array, and use this to specify the repelem inputs:
x = 10;
C = num2cell([ones(1,ndims(A)-1),x]);
out = repelem(A, C{:})
Note that you will need to consider scalar and column vector A as special cases.
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Emmanouil
Emmanouil 2017 年 2 月 6 日
Works like a charm! I did not know I could do this with a cell array. Thanx!

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KSSV
KSSV 2017 年 2 月 6 日
編集済み: KSSV 2017 年 2 月 6 日
Use a if condition on length(size(A)). If A is 3D your length(size(A)) will be 3 and you have to use repelem(A,1,1,x). Like wise if A is 4D, length(size(A)) will be 4.
  3 件のコメント
KSSV
KSSV 2017 年 2 月 6 日
Let it be..you can generate [1 1 x] using [ones(length(size(A))-1) x]
Emmanouil
Emmanouil 2017 年 2 月 6 日
I know I can do this, this was my initial intention as I write in the question. The problem is that the expression repelem(A,[1,1,x]) is not valid.

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