How can I use a string input in a "for" loop to get a matrix of names?
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for i=0:2
a(i)=input('enter your name?','s')
end
what's wrong with this code? Matlab cannot read names I give to it. and here is the error: "Subscript indices must either be real positive integers or logicals."
2 件のコメント
Stephen23
2017 年 2 月 1 日
Note: the original question used an if:
if i=0:2
a(i)=input('enter your name?','s')
end
回答 (2 件)
Alexandra Harkai
2017 年 2 月 1 日
The problem with this code is that (in MATLAB) indexing is from 1, not 0. Therefore a(0) is giving you the error.
As for the for loop (not if), if you want 3 inputs:
for i=1:3
a(i)=input('enter your name?','s');
end
1 件のコメント
Star Strider
2017 年 2 月 1 日
That’s not the only problem. For any name longer than one letter, it will throw a
Subscripted assignment dimension mismatch.
error.
You have to use a cell array (notice the curly brackets ‘{}’ designating it as a cell array):
for i=1:3
a{i}=input('enter your name?','s');
end
Note: In all answers and comments, please test your code before posting it if at all possible. If you cannot, always label it as ‘untested code’.
Stephen23
2017 年 2 月 1 日
編集済み: Stephen23
2017 年 2 月 1 日
Your code has multiple mistakes: MATLAB indexing starts from one, you need to use a for loops, and you need to use a cell array:
N = 3;
C = cell(1,N);
for k = 1:N
C{k} = input('enter your name: ','s');
end
You should do the introductory tutorials, because they teach these very basic MATLAB concepts:
And also read this:
0 件のコメント
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