how to store the matrix from for loop?

m=3; 
A=[ 1 1 0];     
B=[0 1 0];
D=B-A;     
d1=m*A;     
for X=0:1:m     
C=d1+D*X     
end

Answer 1

[KSSV]

m=3;
A=[ 1 1 0];
B=[0 1 0];
D=B-A;
d1=m*A;
C = zeros(m+1,length(d1)) ;
for X=1:1:m+1
    C(X,:)=d1+D*X ;
end

[JAGADEESH JAGA]

the answer is really helpful for me.thanks for the answer. could you answer my question m=3; t=[1 0 0; 0 (1/sqrt(2)) (1/sqrt(2))]; v1=0.24; v2=0.956; a=[ 1 1 0]; b=[0 1 0]; p=b-a; d1=m*a; for x=1:1:m+1 c=d1+p*(x-1) f=transpose(c); vndq=t*f; vnq=vndq(1,1); vnd=vndq(2,1); d(x)=abs(v2-vnq)+abs(v1-vnd) n=min(d) end In the given code c row matrix corresponding minimum value of d matrix must be output if the d changes corresponding c matrix should be abtained to that minimum distance using for loop

Answer 2

[Andrei Bobrov]

m=3;
A=[ 1 1 0];
B=[0 1 0];
D=B-A;
d1=m*A;

C = d1 + (0:m)'*D;             % R2016b and later
C = bsxfun(@plus,d1,(0:m)'*D); % R2016a and earlier

[Stephen23]

+1 nice use of MATLAB.

[Andrei Bobrov]

Thank you Stephen!