Histogram for Grouped Data

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Lorenzo Cito
Lorenzo Cito 2016 年 12 月 29 日
コメント済み: Lorenzo Cito 2016 年 12 月 30 日
Good evening,
I'm wondering if there is a way to plot different histograms on the same graph exploiting grouping variables. I know the function boxplot does it on its own, but I'm, wondering if there is a way to do it using histogram(.).
Basically I want to plot the variation for consumption for different age grups/income quintiles/etc which I have stored as categorical variables.
Can anyone help?
Thank you very much in advance!
Lorenzo
  1 件のコメント
dpb
dpb 2016 年 12 月 29 日
W R2014b histcounts and histogram support categorical variables to at least some degree...w/o knowing precisely what your data are and what you want, whether directly out of the box solution or not, can't tell...

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the cyclist
the cyclist 2016 年 12 月 29 日
編集済み: the cyclist 2016 年 12 月 29 日

I don't believe there is a built-in grouping variable capability in histogram, but it is pretty easy to code

% Made-up data
N = 1000;
x = randn(N,1);
% Grouping variable will be either 0 or 1
gv = round(rand(N,1));
% Offset the gv=1 data, so the histograms are more distinct
x(gv==1) = x(gv==1) + 3;
% Plot the two histograms
figure
hold on
histogram(x(gv==0))
histogram(x(gv==1))
legend({'gv=0','gv=1'})
  3 件のコメント
the cyclist
the cyclist 2016 年 12 月 29 日
There are many possible ways to do get the logical array you need from the cell. Here is one:
C = {'Old','New','New'}; % Your grouping
ismember(C,'Old'); % Logical variable pointing to only first one
Lorenzo Cito
Lorenzo Cito 2016 年 12 月 30 日
Thank you very much!

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