I have data as shown, and I am using if statement but it is giving error as, Undefined function 'lt' for input arguments of type 'cell', please help?

ca =

    [ 1.3589]
    [ 7.9773]
    [28.2728]
    [28.2728]
    [      0]
    [      0]
    [      0]
    [      0]
    [      0]
    [      0]
    [ 0.8705]
    [ 7.4681]
    [28.2728]
    [37.0303]
    [      0]
    [      0]
    [      0]
    [      0]
    [      0]
    [      0]

 if (0<ca)&&(ca>70)

        do this

else

       do this

end

[Thorsten]

Do you want to do "this" it the condition is true for all elements, or do you want to check each individual cell? And what should happen if the cell is empty?

[Sachin Patil]

I want to check for each individual cell. If cell is empty it should be in else condition.

Answer 1

[Star Strider]

You can do the comparison with cellfun. I am not certain what your code is doing, so this function can do element-by-element comparisons in a loop, or you can create a logical vector from the entire ‘ca’ cell array:

LF = @(x) cellfun(@(x) ((0<x) & (x>70)) & ~isempty(x), x, 'Uni',0);     % Element-By-Element Comparison Function

Lv = LF(ca);                                                            % Entire Vector Comparison

Note that none of the elements in ‘ca’ will test true for your conditions.

[Stephen23]

Sachim Patil's "Answer" moved here:

hi Star Strider you said that none of the elements in ‘ca’ will test true for your conditions, why so?

[Stephen23]

@Sachim Patil: because you wrote that one condition is ca>70, and none of the elements of ca are greater than 70. If no element is greater than 70, how do you expect ca>70 to be true ?

[Sachin Patil]

@Star Strider: Oh I am sorry, actually it is less than 70. done by mistake.

[Star Strider]

Then my function becomes:

LF = @(x) cellfun(@(x) ((0<x) & (x<70)) & ~isempty(x), x, 'Uni',0);     % Element-By-Element Comparison Function