# How to Delete Rectangles with Loops

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Salvador Montes 2016 年 7 月 18 日
コメント済み: Image Analyst 2016 年 7 月 18 日
Hello,
I am hoping that someone will help me with a problem I am having. I am trying to make a for loop in order to remove a number of given rectangles. However, I have notice that when I run the code and debug it, the deletion is not shown on the graph. I am not sure how to approach this. Even if this may be a simple problem, I would appreciate any input on this situation.
The Code:
axis([0 20 0 5])
rectangle('Position',[0,1,1,1])
rectangle('Position',[1,1,1,1])
rectangle('Position',[2,1,1,1])
rectangle('Position',[3,1,1,1])
rectangle('Position',[4,1,1,1])
rectangle('Position',[5,1,1,1])
rectangle('Position',[6,1,1,1])
rectangle('Position',[7,1,1,1])
rectangle('Position',[8,1,1,1])
rectangle('Position',[9,1,1,1])
rectangle('Position',[10,1,1,1])
rectangle('Position',[11,1,1,1])
rectangle('Position',[12,1,1,1])
rectangle('Position',[13,1,1,1])
rectangle('Position',[14,1,1,1])
rectangle('Position',[15,1,1,1])
x=15;
for i=1:10
h=rectangle('Position',[x,1,1,1])
H=findobj(h)
delete(h)
x=x-1;
M(i)=getframe
end
movie(M)
Thank you in advance.

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### 採用された回答

Stephen23 2016 年 7 月 18 日

You are drawing every rectangle twice: once hardcoded before the loop, and once inside the loop. This means deleting one of them has no effect because the other is still visible. Try this:
axis([0,20,0,5])
V = 1:15;
for k = V
hnd = rectangle('Position',[k,1,1,1]);
M(k)=getframe;
delete(hnd)
end
movie(M)
##### 5 件のコメント表示非表示 4 件の古いコメント
Image Analyst 2016 年 7 月 18 日
No, it would be the 'units' property of the axes that you're drawing the rectangles on.

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