Error using floor() and ceil() for specific values between o and 1
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Good afternoon,
I'm implementing a function that receive a value and look for this value inside of a matrix. The matrix have just integer values, but the value inside the function is not integer. To solve this problem i'm using the following idea:
%The function receive the value of beta;
%find the first index of the matrix that represents a bigger value
% (Ex: if beta is 8.5, try to find the index that gives the value 9)
index_beta_i_sup = find(Re_36e4 == ceil(beta)); %matrix
beta_i_sup = ceil(beta);
if isempty(index_beta_i_sup) %if the value of beta is not found, I increment +1 until find it
while isempty(index_beta_i_sup)
beta_i_sup = beta_i_sup+1;
index_beta_i_sup = find(Re_36e4 == beta_i_sup);
end
end
The same idea to try to find the lower index value inside the matrix:
index_beta_i_inf = find(Re_36e4 == floor(beta));
beta_i_inf = floor(beta);
if isempty(index_beta_i_inf)
while isempty(index_beta_i_inf)
beta_i_inf = beta_i_inf-1;
index_beta_i_inf = find(Re_36e4 == beta_i_inf);
end
end
When I run the problem using values: 1 < beta < 180 the function works perfectly.I put some prints to check if I run the code with beta <1, the following error appear.
beta= 8.700000e-01;
beta_sup= 1;
index_beta_i_sup = 53 %(inside the matrix - OK)
beta= 8.700000e-01;
beta_inf= 0;
index_beta_i_inf = 52 %(inside the matrix - OK)
| _*%this part is not suppose to be here in the code!*_|
*beta= 104;
beta_inf= 155;
index_beta_i_inf = 206*
Error: Index exceeds matrix dimensions.
My matrix has no 206 elements, that's why I have problem, but i didn't intend to make this last calculation, appear alone *(this beta=104). The problem is just for floor().
If I use the value of beta=-0.87, the problem will be in the ceil() function, that will return this beta=104.
Thanks for your support.
2 件のコメント
dpb
2016 年 6 月 12 日
Are you simply looking for the nearest integer value in the array to a non-integer input? How about
y = interp1(Y,Y,beta,'nearest');
where Y is your array of integer values, beta is the looked for nearest value to be found.
Mateus Roberto Urio
2016 年 6 月 12 日
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その他の回答 (1 件)
dpb
2016 年 6 月 12 日
" just trying to figure out the index of the nearest value inside the matrix (superior and inferior)."
Then look for that directly...
I assume Y is ordered --
iLess=find(Y<beta,1,'last'); % last Y < beta location
iPlus=find(Y>beta,1,'first'); % first Y > beta location
If there's no value satisfying the inequality, will return empty, []
3 件のコメント
Guillaume
2016 年 6 月 12 日
I believe the OP wants the index of the nearest value greater/smaller than beta, not the first value that happens to be above/below beta.
dpb
2016 年 6 月 12 日
That's what he'll get with the single caveat of the array being ordered--it's the last under and the first after. Unless they're not ordered those will also be closest but in that case you've got to do a MIN() on the difference to find the nearest.
Mateus Roberto Urio
2016 年 6 月 13 日
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